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2 years ago

7 d^2 +10 when d = 3

Mathematics

2 answers:

tankabanditka [31]2 years ago

8 0

Hey. Let me help you out

First, let's rewrite the equation in order to minimize confusion. The way you wrote it makes it hard to vision it.

$7d^2+10d=3$

Now, we just replace the variable d with a value we have.

$7(3^2)+10$

Three to the power of two is going to equal to 9.

$7*9+10$

Seven times nine is 63.

$63+10$

Finally, 63 plus 10 is going to be 73.

Answer is 73

user100 [1]2 years ago

5 0

Answer:

d = 3/7 = 0.429

d = 1

Step-by-step explanation:

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0.3(n-5)=0.4-0.2 solve for n!

mariarad [96]

Answer:

$n = 5.67$

Step-by-step explanation:

0.3(n-5)=0.4-0.2

0.3(n-5) = 0.2

Dividing 0.3 both side

$\frac{0.3(n-5) }{0.3} = \frac{0.2}{0.3}$

$n-5 = 0.67$

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2 years ago

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gladu [14]

N/4 less than or equal to 5

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3 years ago

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insens350 [35]

Answer:

3,158

Step-by-step explanation:

The formula is :

h(x)=-49(x)-125

h(-67)=(-49)*(-67)-125

h(-67)=3283-125

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2 years ago

Can u guys PLEASE answer this question ASAP. A line passes through the point (2,4) and has a gradient 2. Find the y-coordinate o

Veseljchak [2.6K]

y=2

Step-by-step explanation:

Make an equation of straight line by using the formula :y= mx+c

put the x-value of point (2,4) which is 2 and the gradient,m which is 2 into the straight line equation:

y=2x +c

So you need to find the y-intercept to complete the equation, therefore:

when y=0,

0=2(2)+c

c=-4

next the question ask to find the y-coordinate when x =3, therefore you just need to replace x in the equation with 3:

y=2(3)-4

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7 0

2 years ago

After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6,3), B'(-2, 1)

Fed [463]

Answer:

A(3, -6)
B(1, 2)
C(7, -1)

Step-by-step explanation:

Rotation by -90° about the origin is the transformation ...

(x, y) ⇒ (y, -x)

So, your pre-image points are ...

A'(6, 3) ⇒ A(3, -6)

B'(-2, 1) ⇒ B(1, 2)

C'(1, 7) ⇒ C(7, -1)

8 0

2 years ago