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sweet-ann [11.9K]
1 year ago
9

Help what is the measure of the angle x?

Mathematics
1 answer:
Schach [20]1 year ago
7 0

Answer:

x = 20

Step-by-step explanation:

There is a right angle which is 90 degrees. Part of the angle is 30 degrees, so the other measure is 60 degrees, which is the 3x.

Make an equation.

3x = 60

Divide both sides by 3

3x/3 = 60/3

x = 20

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2 years ago
Two consecutive even integers have a sum of 14. The equation that would be used to solve this
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X + x + 2 = 14
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Evaluate the double integral.
Fynjy0 [20]

Answer:

\iint_D 8y^2 \ dA = \dfrac{88}{3}

Step-by-step explanation:

The equation of the line through the point (x_o,y_o) & (x_1,y_1) can be represented by:

y-y_o = m(x - x_o)

Making m the subject;

m = \dfrac{y_1 - y_0}{x_1-x_0}

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

m= \dfrac{2-1}{1-0}

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

m = \dfrac{1-2}{4-1}

m = \dfrac{-1}{3}

∴

y-2 = -\dfrac{1}{3}(x-1)

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg)   dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ([y^2(-4y+8)] \bigg ) \ dy

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\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]

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\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{-45+56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{11}{3}\bigg]

\iint_D 8y^2 \ dA = \dfrac{88}{3}

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8/2z=15/60 .solve proportion.
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Answer:

d. both the slope and price elasticity of demand are equal to 0.

Step-by-step explanation:

In order to graph the demand curve, the quantity demanded is plotted along x-axis and the price is plotted along y-axis. An image attached below shows the horizontal demand curve.

Horizontal demand curve, as its name indicates, is a horizontal line which is parallel to x-axis. Since, the slope of any line parallel to x-axis is 0, we can conclude that the slope of Horizontal demand curve is 0.

A horizontal demand curve can be observed for a perfectly competitive market. Since, its a perfect competition, the price of a product by all competitors will be the same. In this case, if a firm decides to increase the price, he will loose his market share as no customer will buy the product at increased price. They will rather go with the other competitor who is offering a similar product at lower price.

On the other hand, if a competitor decides to lower his price in such case, he will experience loss. Therefore, the competitors do not have the option to change the price. Therefore, we can say the price elasticity of demand in this case is 0.

So, option D describes the horizontal demand curve correctly.

3 0
2 years ago
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