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olga_2 [115]
3 years ago
13

After solving an equation, you end up with integers on both sides of the equation. What can you interpret about the equation are

the same?
Select ALL that apply:  Contradiction  Identity  Conditional
 Infinitely many solutions  No solution  One solution
Mathematics
1 answer:
murzikaleks [220]3 years ago
5 0

Answer:

The equation is:

An identity

Has infinitely many solutions

No solution

Step-by-step explanation:

Because there is integers on both sides, we know that any attempts to fix this will either cause an identity, or a false numerical equation(an identity but <em>w r o n g</em>).(Note, an identity can either mean 2 = 2 or x = x).

Identities have infinite solutions, because it does not matter what you put in, the equation will always be true. False equations do not have a solution because they aren't even true equations.

Hope this helps!

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I got c which is 100 but I don’t know how jerry got A
Anna007 [38]

Choice C is the correct answer because

\frac{(6+2)^3-12}{5}\\\\\frac{(8)^3-12}{5}\\\\\frac{512-12}{5}\\\\\frac{500}{5}\\\\100\\\\

So in short, \frac{(6+2)^3-12}{5}=100\\\\

------------------------------------------

The mistake Jerry likely made was that he only cubed the 2 and didn't realize the 6 was part of that cubing process. It seems he didn't add first and decided to cube before adding.

This is probably what steps Jerry did

\frac{6+2^3-12}{5}\\\\\frac{6+8-12}{5}\\\\\frac{14-12}{5}\\\\\frac{2}{5}\\\\

But as mentioned, those steps are incorrect because the 6 is part of the cubing operation. In other words, Jerry should have added the 6+2 first before cubing afterward (due to PEMDAS determining the order of operations).

Or you could think of it like this

\frac{(6+2)^3-12}{5}\\\\\frac{(6+2)(6+2)(6+2)-12}{5}\\\\\frac{(8)(8)(8)-12}{5}\\\\\frac{512-12}{5}\\\\\frac{500}{5}\\\\100

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