Describe a machine or situation where it is important to have the ability to turn magnetic power on and off.

If 50.0 g of KCl reacts with 50.0 g of O2 to produce KClO3 according to the following equation, how many grams of KClO3 will be

Sliva [168]

Answer:

A. 82.2g of KClO3

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3

C. Formula equation:

2KCl + 3O2 —> 2KClO3

Explanation:

The balanced equation for the reaction. This is given below:

2KCl + 3O2 —> 2KClO3

Next, we shall determine the masses of KCl and O2 that reacted and the mass of KClO3 produced from the balanced equation. This is illustrated below:

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Summary:

From the balanced equation above:

149g of KCl reacted.

96g of O2 reacted.

245g of KCl were produced.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

149g of KCl reacted with 96g of O2.

Therefore, 50g of KCl will react with = (50 x 96)/149 = 32.21g of O2.

Since a lesser mass of O2 ( i.e 32.21g) than what was given (i.e 50g) is needed to react completely with 50g of KCl, therefore, KCl is the limiting reactant and O2 is the excess reactant.

A. Determination of the mass of KClO3 produced from the reaction.

In this case the limiting reactant will be used.

From the balanced equation above,

149g of KCl reacted To produce 245g of KClO3.

Therefore, 50g of KCl will react to produce = (50 x 245)/149 = 82.2g of KClO3.

Therefore, 82.2g of KClO3 is produced from the reaction.

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3.

C. Formula equation:

2KCl + 3O2 —> 2KClO3

4 0

4 years ago

Help cococococo cococococo doing this for the points or whatever it is cococo

finlep [7]

Answer:

what is cocococococo?

Explanation:

isnt it like a plant for choclate?

5 0

3 years ago

Read 2 more answers

What differentiates the isotopes of an element?

slega [8]

An isotope is different from an element by the number of neutrons it has.

4 0

4 years ago

Read 2 more answers

How many liters of NH 3 are needed to react completely with 30.0 L of NO (at STP)?

aleksklad [387]

Answer:

20.8 Lof NH₃ are needed for the reaction

Explanation:

This is the reaction:

4 NH₃ + 6 NO → 5N₂ + 6H₂O

and the info. we need

Ammonia density = 0,00073 g/mL

Let's determine the moles of NO at STP by the Ideal Gases Law equation

P . V = n . R .T

1atm . 30L = n . 0.082 . 273K

(1atm . 30L) / (0.082 . 273K) = n → 1.34 moles of NO

Let's find out the amount of ammonia that should react

6 mol of NO react with 4 mol of ammonia

1.34 mol of NO will react with (1.34 .4)/6 = 0.893 moles of ammonia

Molar mass NH₃ = 17 g/m

0.893 mol . 17 g/m = 15.19 g of ammonia

Ammonia density = 0,00073 g/mL = NH₃ mass / NH₃ volume

0,00073 g/mL = 15.19 g / NH₃ volume

NH₃ volume = 15.19 g / 0,00073 g/mL → 20805.5 mL ⇒ 20.8 L

6 0

3 years ago

Calcule la masa en gramos de cloruro de hidrógeno (HCl) que se forma cuando 5.6 L de hidrógeno molecular, medido a TPE, reaccion

AveGali [126]

Calculate the mass in grams of hydrogen chloride (HCl) that is formed when 5.6 L of molecular hydrogen, measured at TPE, reacts with an excess of gaseous molecular chlorine. MHCl = 36.5 g/mol

H2(g) + Cl2(g) → 2HCl(g)

Answer:

18.25g

Explanation:

The reaction equation is given as;

H₂ + Cl₂ → 2HCl

Given parameters:

Volume of hydrogen gas = 5.6L

The reaction occurs at STP.

Solution:

To solve this problem, let us find the number of moles of the hydrogen as;

At STP;

22.4L of a gas has 1 mole;

5.6L of Hydrogen as will have $\frac{5.6}{22.4}$ = 0.25mole

From the balanced reaction equation;

1 mole of H₂ will produce 2 mole of HCl

0.25 mole of H₂ will produce 2 x 0.25 = 0.5mole of HCl

The mass of HCl';

Mass of HCl = number of moles x molar mass

Mass of HCl = 0.5 x 36.5 = 18.25g

7 0

3 years ago