Answer:

Explanation:
It is given that,
Original temperature, 
Original volume, 
We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.
According to Charles law, at constant pressure, 
It would means, 
T₂ = ?

So, the new temperature is 261.46 K.
Half life is the time taken for a radioactive isotope to decay by half its original mass. In this case the half life of carbon-14 is 5.730 years.
Using the formula;
New mass = original mass × (1/2)^n; where n is the number of half lives (in this case n=1 )
New mass = 2 g × (1/2)^1
= 1 g
Therefore; the mass of carbon-14 that remains will be 1 g
Answer:
Consider how the speaker begins the speech, the support given in the body of the speech, and how the speaker concludes. Listen for changes in tone. Listen for how the speaker uses delivery techniques such as pauses, pace, voice, metaphors and symbolism, repetition and parallelism, and vocabulary.
Explanation:

The chemical property deals with the ability of a substance being able to burn is called combustibility [ option b ] .
<u>More</u><u> to</u><u> know</u><u> </u><u>:</u><u>-</u>
<em>1</em><em>)</em><em> </em><em>Combustion</em><em> </em><em>:</em><em>-</em>
Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives out heat.
The fuel can be any one of the 3 states of matter that is - solid , liquid & gases .
Examples of combustible substances :-
Solid - Coal
Liquid - Petrol , Disel , etc.
Gas - Hydrogen , Oxygen , etc .
Answer:
d. oligomer it is the correct answer also if you would just search that up it pops up