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3 years ago

Plz help me I need it

Mathematics

1 answer:

valina [46]3 years ago

5 0

<h3>Answers:</h3>

b = 92 degrees (choice B)

c = 92 degrees (choice D)

d = 92 degrees (choice F)

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Explanation:

Angles a and b are supplementary because they form a straight angle when combined. The two angles add to 180

a+b = 180

88+b = 180 ... plug in a = 88

b = 180-88 ... subtract 88 from both sides

b = 92

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Angles b and c are congruent because they are alternate interior angles. Alternate interior angles are congruent when dealing with parallel lines.

Since the diagonal entrance ramps are parallel, this means the corresponding angles c and d are congruent.

Since b = 92, this means c = 92 and d = 92 also.

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9.45×10^6 in standard form

FrozenT [24]

Answer:

That is written in standard form, no changes are needed.

9.45×10^6 is the answer

7 0

2 years ago

the speed of a stream is 4mph. If a boat travels 92 miles downstream in the same time that it takes to travel 46 miles upstream,

Elanso [62]

Answer:

12 miles per hour

Step-by-step explanation:

Let speed of boat in still water be "x"

and speed of current be "c"

So, downstream rate would be "x + c"

And, upstream rate would be "x - c"

Now, given c = 4

We can use the distance formula, D = RT, where

D is distance, R is rate, and T is time

to solve this.

Downstream:

D = RT

92 = (x+4)(t)

Upstream:

D = RT

46 = (x-4)(t)

Both the times are same, we can equate both the times. Lets simplify first:

t = 92/(x+4)

and

t = 46/(x-4)

Equate:

$\frac{92}{x+4}=\frac{46}{x-4}$

Now, cross multiply and solve for x to get our answer:

$\frac{92}{x+4}=\frac{46}{x-4}\\92(x-4)=46(x+4)\\92x-368=46x+184\\46x=552\\x=12$

Speed of Boat (in still water) = 12 mph

6 0

3 years ago

Here’s a graph of a linear function. Write the equation that describes that function. Express it in slope-intercept form.

Ipatiy [6.2K]

Answer:

y=4x-1

Step-by-step explanation:

Slope-intercept form is written in y=mx+b

*m=slope

*b=y-intercept

From what I see,

the line hits the points (0,-1) and (1,3)

Slope is the rise (change in the y-coordinate) of the line divided by the run (change in the x-coordinate).

4÷1=4

Slope=4

y=4x+b now

The y-intercept is the value of y when the line meets the y-axis

It seems to meet at (0,-1)

So we end up with...

y=4x-1 as our equation

8 0

3 years ago

Write an exponential function in the form y = abx that goes through points (0,16)<br>and (2,400).

barxatty [35]

Answer:

y = 16 $(5)^{x}$

Step-by-step explanation:

Use the given points to find the values of a and b

Using (0, 16), then

16 = a $b^{0}$ ( $b^{0}$ = 1 ), thus

a = 16

y = 16 $b^{x}$

Using (2, 400), then

400 = 16b² ( divide both sides by 16 )

b² = 25 ( take the square root of both sides )

b = $\sqrt{25}$ = 5

Thus

y = 16 × $5^{x}$ ← exponential function

5 0

3 years ago

The number m of miles a long-distance cyclist travels during today's ride can be modeled by the function m(t)=11t+55, where t re

iVinArrow [24]

Step-by-step explanation:

m(t) = 11t + 55

the slope is always the factor of the variable, so here the slope is 11.

since t is the number of hours riding (after the noon rest stop), the slope (11) is actually the mean speed the rider is going (after the noon rest stop) : with every hour riding the cyclist goes another 11 miles, so this speed is 11 mph.

the y-intercept is the m value when t = 0, because here in our example y (the result variable) is renamed m.

it is here 55.

t = 0 means no time riding yet, so 55 is the "starting value" of the function. that means that the cyclist traveled already 55 miles earlier that day before the noon rest stop.

the cyclist can only ride until 6pm. but we don't know how long the noon rest stop is (i.e. when he continues riding after the rest stop).

so I need to make some assumptions :

the mean speed (11 mph) after lunch break, and the y-intercept (55) suggest to me that the cyclist was riding 5 hours before the stop (5×11 = 55), and will also ride 5 hours after the stop (= from 1pm to 6pm).

if this is wrong, and the cyclist starts at e.g. 12pm, then please just adjust the following numbers accordingly.

but here again, I am assuming the cyclist will go from 1pm to 6pm (for 5 hours).

the domain is the interval or set of all valid values of the input variable (here t) : all real numbers in [0 .. 5].

the "timer" starts at 0 right at the end of the noon test stop. and then the cyclist can go max. 5 hours. and I assume any part of an hour is valid, so we use real numbers instead of e.g. whole numbers.

the range is the interval or set of all valid values of the result variable (here m) : all real numbers in [55 .. 110].

for t = 0 we have m = 55. and this goes continuously up with t until t = 5, leading to 11×5 + 55 = 55+55 = 110.

7 0

2 years ago