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Andre45 [30]
3 years ago
5

A man realizes he lost the detailed receipt from the store and only has the credit card receipt with the after-tax total. If the

after-tax total was $1,814.31, and the tax rate in the area is 6.1%, what was the pre-tax subtotal?
Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

For the pre-rax subtotal x you have this equation

   x + 0.074x = 408.12  dollars.

   x*(1 + 0.074) = 408.12

   1.074x = 408.12  ====>  x = 408.12%2F1.074. 408.12/1.074

Step-by-step explanation:

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MaRussiya [10]

Answer:

Step-by-step explanation:

Angle C and angle with 120 degrees measure are alternate and their measurement is equal so C = 120

angle C and angle B are supplementary and so their sum is equal to 180

B = 180 - 120

B = 60

angle D and angle B are also alternate so their measure is also equal to each other therefore

D = 60

7 0
3 years ago
What is the domain of g
olga nikolaevna [1]

Answer:

A

Step-by-step explanation:

The domain of g(x) is the set of all real numbers. Meaning that all the numbers between the min and max of g would be -7 ≤ x ≤ 7.

6 0
1 year ago
Question:
Tamiku [17]

Answer:

<h2>      x₁ = - 2 + √2 ,   x₂ = - 2 - √2</h2>

Step-by-step explanation:

3x^2 + 12x + 6 = 0\\\\a=3\,,\ b=12\,,\ c=6\\\\\\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\ x=\dfrac{-12\pm\sqrt{12^2-4\cdot3\cdot6}}{2\cdot3}=\dfrac{-12\pm\sqrt{144-72}}{2\cdot3}=\dfrac{-12\pm\sqrt{72}}{2\cdot3}=\dfrac{-12\pm6\sqrt{2}}{6}\\\\x_1=\dfrac{6(-2+\sqrt{2})}{6}=-2+\sqrt2\\\\x_2=\dfrac{6(-2-\sqrt{2})}{6}=-2-\sqrt2

8 0
3 years ago
Write the expression without radicals, using only positive exponents
Mamont248 [21]

Answer:

\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}

Step-by-step explanation:

∵∛x = (x)^1/3

∴ \sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}

So you can replace the radicals by fractional exponents

7 0
3 years ago
Read 2 more answers
5c + 3 ≥ 6x -8<br><br> Solve the following inequality for cc. Write your answer in simplest form.
irina [24]

Answer:

c≥2(x-2) ÷ 5

Step-by-step explanation:

5c+3≥6x-8

5c ≥6x-8-3

5c≥6x-12

c≥(6x-12) ÷ 5

c≥ 2(x-2) ÷5

3 0
2 years ago
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