A sort function sorts in an ascending or desceding order
The true statement is that the function would sort in decreasing order.
<h3>What is a sort function?</h3>
A sort function is a code segment that is used to reorder a list in ascending or descending order, when called or evoked
<h3>The order of the sort function</h3>
The code segment is given as:
if (list[index] < list[index + 1]) {
temp = list [index];
list[ index] = list [index +1];
list[index +1] = temp;
}
In the above code, we can see that the code compares a list element with the next element on the list, and the larger value comes to the front
This means that the sort function sorts in decreasing order
Read more about code segments at:
brainly.com/question/16397886
Answer:
Option B: The text field x will have the value "Tiny Tim" and the user will be able to change its value.
Explanation:
- The first statement say: x.setEditable(true);
It will only change the property of the text present in x to editable. This means that whenever the text value needs to change the user can edit it.
- The second statement say: x.setText("Tiny Tim");
It will put the text "Tiny Tim" into the attribute x and present it as the output or result.
Answer: This is a python code
def lightyear():
rate=3*100000000 //speed of light
seconds=365*24*60*60 //number of seconds in 1 year
return str((rate*seconds)/1000)+" km" //distance=speed x time
print(lightyear()) //will print value of light hear in kilometers
OUTPUT :
9460800000000.0 km
Explanation:
In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
