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matrenka [14]
3 years ago
13

1. Define a C++ function with the name evaluateBook. The function receives as one argument the name of the file to be processed

(i.e., the book's file). So that if you pass the English version, we will see the results only for that language.
2. Function evaluateBook opens the file, reads it, analyzes it, and prints the answer to the following questions:



a. What it the total number of text lines in the file?

b. What it the number of text lines without any lower-case letter? To answer this question, write and call the function testLowerCase.

c. What it the number of text lines without any number? To answer this question, write and call the function testNumber.

d. What is the total number of visible characters (so, excluding invisible codes such as '\n') ? To answer this question, write and call the function countCharacters.

e. What is the total number of letters (i.e., excluding symbols, numbers, etc.)? To answer this question, write and call the function countLetters.

f. How many times each of the following punctuation symbols appear: comma, period, double quotes, single quotes ?

g. What is the most popular letter (regardless of its case) ? (update: assume it is a vowel)

h. The word "et" in French means "and". How many times does this word appear? The function should search for both words, so that if you pass the English version, the count for "et" will be likely zero. Also, ignore the case, but do not count a matching if part of another word, such as "Andrew".
Computers and Technology
1 answer:
katovenus [111]3 years ago
4 0

Answer:

#include <iostream>

#include<string>

#include<fstream>

using namespace std;

void evaluateBook(string bookName);

int countCharacters(string bookLine);

int countLetters(string bookLine);

int totalPunctuations(string bookLine);

int main()

{

  evaluateBook("demo-book.txt");

  return 0;

}

int countCharacters(string bookLine) {

  return bookLine.length();

}

int countLetters(string bookLine) {

  int counter = 0;

  for (int i = 0; i < bookLine.length(); i++) {

      if ((bookLine[i] >= 'a' && bookLine[i] <= 'z') || (bookLine[i] >= 'A' && bookLine[i] <= 'Z')) {

          counter++;

      }

  }

  return counter;

}

int totalPunctuations(string bookLine) {

  int counter = 0;

  for (int i = 0; i < bookLine.length(); i++) {

      if (bookLine[i]=='\.' || bookLine[i]=='\,' || bookLine[i]=='\"' || bookLine[i]=='\'') {

          counter++;

      }

  }

  return counter;

}

void evaluateBook(string bookName) {

  ifstream in(bookName);

  int totalVisibleCharacters = 0,totalLetters=0,numberOfPunctuations=0;

  if (!in) {

      cout << "File not found!!\n";

      exit(0);

  }

  string bookLine;

  while (getline(in, bookLine)) {

      totalVisibleCharacters += countCharacters(bookLine);

      totalLetters += countLetters(bookLine);

      numberOfPunctuations += totalPunctuations(bookLine);

  }

  cout << "Total Visible charcters count: "<<totalVisibleCharacters << endl;

  cout << "Total letters count: " << totalLetters << endl;

  cout << "Total punctuations count: " << numberOfPunctuations<< endl;

}

Explanation:

  • Create a function that takes a bookLine string as a parameter and returns total number of visible character.
  • Create a function that takes a bookLine string as a parameter and returns total number of letters.
  • Create a function that takes a bookLine string as a parameter and returns total number of punctuation.
  • Inside the evaluateBook function, read the file line by line and track all the information by calling all the above created functions.
  • Lastly, display the results.

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Answer:

The program required is in the explanation segment.

Explanation:

Program :

import math

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i=2

while i<=100:

if i %2 ==0:

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sum=0

while i<=100:

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#c. displays the powers of 2 from 1 up to 256.

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i=0

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#d. displays the sum of all odd numbers between a and b (inclusive), where a and b are inputs

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temp=a

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while a<=b:

if a%2!=0:

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sum=sum+a

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print("\nCompute the sum of the odd digits in an integer ")

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