Answer:
a) 0.19
b) 0.9689
c) ≈ 6 cars
Step-by-step explanation:
Rate at which cars arrive = 12 cars/hour = 1/5 cars/minute
time needed by each car to complete ATM transaction = 6 minutes = 1/6 car/minute
capacity of lane = 10 car
n = 10
<u>a) Calculate the probability of an arriving not using the ATM because the line is full</u>
p ( not using the ATM ) = 0.19
<u>b) probability that a car will not be able to use the ATM machine immediately on arrival</u>
P ( n > 0 ) = 1 - Po
= 1 - 0.0311 = 0.9689
<u>c) Average number of cars in the lane </u>
Lq = 5.74 ≈ 6 cars
attached below is the detailed solution
3 lemons cost = Rs. 5
Each lemon cost = Rs. 5/3
2 lemons Cost = Rs. 4
Each lemon cost =

Total Cost price of Each lemon =

LCM = 3

Each lemon Cost =



Selling price of 5 lemons = 9
Selling price of 1 lemon = 9/5






Remaining shirts to be ironed = 1 - 1/4 = 3/4
Fraction of shirts Lenox will iron each day = (3/4)/5 = 3/20
No of shirts to be ironed on thursday and friday = 2(3/20 x 40) = 3 x 6 = 18.