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Maksim231197 [3]
3 years ago
15

Karleigh walks 5/8 mile to school every day.How far does she walk to school in 5 days

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Answer:

3\frac{1}{8}=3.125 miles

Step-by-step explanation:

We have been given that Karleigh walks 5/8 mile to school every day.

To find the distance walked by Karleigh in 5 days we will multiply distance traveled in one day by total number of days.

\text{Distance walked by Karleigh in 5 days}=\frac{5}{8}\times 5

\text{Distance walked by Karleigh in 5 days}=\frac{25}{8}

\text{Distance walked by Karleigh in 5 days}=3\frac{1}{8}=3.125

Therefore, Karleigh walked 3\frac{1}{8}=3.125 miles to school in 5 days.

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seropon [69]
The answers 15 because we have two negatives it's always a positive and 3×5 is 15
5 0
3 years ago
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sam is 12 in four years his age will be 2/3 the age of his cousin like how old will luke be in two years
Mazyrski [523]

Answer:

he will be 17 in

Step-by-step explanation:

8 0
3 years ago
Seventy-six percent of sunflower seeds will germinate into a flower, and a sample of 800 such sunflower seeds is randomly select
ollegr [7]

Answer:

12.08

Step-by-step explanation:

For each sunflower, there are only two possible outcomes. Either it germinates, or it does not. The probability of a sunflower germinating is independent of other sunflowers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Seventy-six percent of sunflower seeds will germinate into a flower

This means that p = 0.76

Samples of 800:

This means that n = 800

The standard deviation for the number of sunflower seeds that will germinate in such samples of size 800 is:

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{800*0.76*0.24} = 12.08

5 0
3 years ago
Tell whether the sequence 1/3, 0, 1, -2 ... is arithmetic, geometric, or neither. Find the next three terms of the sequence.
max2010maxim [7]

Answer:

A. neither; 7, -20, 61

Step-by-step explanation:

The sequence 1/3, 0, 1, -2 ...

The difference between the terms are; -1/3, 1, -3......

Looking the difference between consecutive terms in the sequence, we can predict the next differences between the following terms, as the differences form a geometric sequence;

Therefore; -1/3, 1, -3, 9, -27, 81

Thus; the sequence will be;

1/3, 0, 1, -2 , (-2+9), (-2+9+-27), (-2+9+-27+81)

1/3, 0, 1, -2, 7, -20, 61

Hence the next three terms are; 7, -20, 61

6 0
2 years ago
2. When a large truckload of mangoes arrives at a packing plant, a random sample of 150 is selected and examined for
kirza4 [7]

a) The 90% confidence interval of the percentage of all mangoes on the truck that fail to meet the standards is: (7.55%, 12.45%).

b) The margin of error is: 2.45%.

c) The 90% confidence is the level of confidence that the true population percentage is in the interval.

d) The needed sample size is: 271.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The variables are listed as follows:

  • \pi is the sample proportion, which is also the estimate of the parameter.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.90}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given as follows:

n = 150, \pi = \frac{15}{150} = 0.1

The margin of error is of:

M = z\sqrt{\frac{0.1(0.9)}{150}} = 0.0245 = 2.45\%

The interval is given by the estimate plus/minus the margin of error, hence:

  • The lower bound is: 10 - 2.45 = 7.55%.
  • The upper bound is: 10 + 2.45 = 12.45%.

For a margin of error of 3% = 0.03, the needed sample size is obtained as follows:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.1(0.9)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.1(0.9)}

\sqrt{n} = \frac{1.645\sqrt{0.1(0.9)}}{0.03}

(\sqrt{n}})^2 = \left(\frac{1.645\sqrt{0.1(0.9)}}{0.03}\right)^2

n = 271 (rounded up).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

3 0
1 year ago
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