10x^6y^3 + 20x^3y^2 / 5x^3y =
5x^3y (2x^3y^2 + 4y) / 5x^3y=
<span>2x^3y^2 + 4y
</span>
First you find what the expressions 10x^6y^3 and 20x^3y^2 have in common, and that is 5x^3y, which is the same as the denominator, so you can easily divide them and get 1.
<span>Hope you understand!
</span>
1. we can add them to eliminate y's
3x-4y=-16
<u>-x+4y=24 +</u>
2x+0y=8
2x=8
divide by 2
x=4
sub back
-x+4y=24
-4+4y=24
add 4 both sides
4y=28
divide by 4
y=7
(x,y)
(4,7)
3.
add them to eliminate y's
-5x+3y=12
<u>-2x-3y=-33 +</u>
-7x+0y=-21
-7x=-21
divide both sides by -7
x=3
sub back
-2x-3y=-33
-6-3y=-33
add 6 to both sides
-3y=-27
divide both sides by -3
y=9
(x,y)
(3,9)
1. (4,7)
3. (3,9)
Answer:
-6 and -7
Step-by-step explanation:
Sorry if its wrong
The correct answer would be 10 sides.
Source credit: algebra.com
Answer:
Step-by-step explanation: