Complete question:
A student throws a heavy ball downward off the top of a building with a speed of 18m/s. The ball reaches a speed of 41m/s just before striking the ground. Neglect drag, find the height of the building.
Answer:
The height of the building is 69.235 m
Step-by-step explanation:
Given;
initial velocity of the ball, u = 18 m/s
final velocity of the ball, v = 41 m/s
The height of the building is equal to distance traveled by the ball downward.
Apply the following kinematic equation;
v² = u² + 2gh
where;
g is acceleration due to gravity
h is height of the building
41² = 18² + 2(9.8)h
1681 = 324 + 19.6h
19.6h = 1681 - 324
19.6h = 1357
h = 1357 / 19.6
h = 69.235 m
Therefore, the height of the building is 69.235 m
You need to find the surface area and the volume. The formula for surface area is 4*3.14(pi)*radius^2 which is equal to 6.5144 inches^2 in this case. The amount of rubber needed to fill it is equal to the volume. The formula for volume of a sphere is 4/3*3.14(pi)*radius^3, just plug in the number (remember radius is half of diameter) and that will give you the answer!
Answer:
0.102
Step-by-step explanation:
because 0.102-0.024>0, meaning it has more. also the second number has a . tenth while the first number has 2 hundreths, which is smaller
Answer:
292.5 miles per day
Step-by-step explanation:
The map shows it is 1170 miles from my school to Wall, South Dakota, a place well-advertised in the Midwest. If I want to take 4 days to get there, the required division is ...
... (1170 mi)/(4 da) = 292.5 mi/da
Answer:
D.) In the first 3 hours she had traveled a total of 200 miles
Step-by-step explanation:
By looking at the graph you can just go to the 3 hours mark and go upwards until you land on a whole number, in this case 200!
Hope I helped :)
