V=x^3+5x^2-57x-189
Width: W=(x+3) in = 15 in →x+3=15
Solving for x:
x+3-3=15-3→x=12
With x=12 the Volume would be:
V=(12)^3+5(12)^2-57(12)-189
V=1,728+5(144)-684-189
V=1,728+720-684-189
V=1,575
V=W*D*H
Depth: D
Height: H
with H>D
V=1,575; W=15
Replacing in the equation above:
1,575=15*D*H
Dividing both sides by 15
1,575/15=(12*D*H)/15
105=D*H
3*5*7=D*H
D<H
If D=5→H=3*7→H=21
If D=7→H=3*5→H=15
Answer: Option <span>C. height: 21 in. depth: 5 in.
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Please, see the attached file for another form to solve the problem
There is an example hope it helped
Answer:
B
Step-by-step explanation:
We'll use Natasha's location as 0 on a number line. To the left of her, 51/20 would be negative and 25/4 would be positive.
To find how far apart the dogs are, we would need to add the absolute value of each number:
|-51/20| + |25/4| however, this can also be rewritten as:
25/4 - (-51/20)
Answer:
100 x 13/16 x 25b = 4
18 3/4 = 25b/4
b=25/4
b= 6.25
Step-by-step explanation:
25/4 = 6 1/4 last weekend and 18 3/4 this weekend.
Fill the 200mL beaker all of the way. Using the water in that beaker, fill and pour out the 30mL twice and the 40mL three times. You should be left with 20mL in the 200mL beaker.