The absolute value functions that contains the points are:
- f(x) = |x| + 2
- f(x) = |-x| + 2
<h3>Which could be the function represented by this graph?</h3>
Here we have the points (-3, 5), (0, 2), and (3, 5). We want to see which ones of the given functions have that points.
To check that, we need to evaluate the functions in the first value of each point and see if the outcome is the second value of the correspondent point.
For example, for the first equation:
- f(-3) = |-3| + 2 = 5 so it has the point (-3, 5)
- f(0) = |0| + 2 = 2 so it has the point (0, 2)
- f(3) = |3| + 2 = 5 so it has the point (3, 5).
The other option that also contains these 3 points is:
f(x) = |-x| + 2
- f(-3) = |3| + 2 = 5 so it has the point (-3, 5)
- f(0) = |-0| + 2 = 2 so it has the point (0, 2)
- f(3) = |-3| + 2 = 5 so it has the point (3, 5).
And all the other options can be trivially discarded (by evaluating them).
So the two correct options are:
- f(x) = |x| + 2
- f(x) = |-x| + 2
If you want to learn more about absolute value functions:
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Option C ,
40 degrees
Because angle Z was 70 (isosceles triangle)
Then 180-140=40 degrees
5 x (10^2) =
5 x 100 = 500
I guess you mean:
4,5 x (10^2) =
4,5 x 100 =
450
Which acctually is a valid answer.
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Equation of regression line :
Yˆ = −114.05+2.17X
X = Temperature in degrees Fahrenheit (°F)
Y = Number of bags of ice sold
On one of the observed days, the temperature was 82 °F and 66 bags of ice were sold.
X = 82°F ; Y = 66 bags of ice sold
1. Determine the number of bags of ice predicted to be sold by the LSR line, Yˆ, when the temperature is 82 °F.
X = 82°F
Yˆ = −114.05+2.17(82)
Y = - 114.05 + 177.94
Y = 63.89
Y = 64 bags
2. Compute the residual at this temperature.
Residual = Actual value - predicted value
Residual = 66 - 64 = 2 bags of ice
We have the following functions:
f (x) = x ^ 2 + 1
g (x) = 1 / x
Multiplying we have:
(f * g) (x) = (x ^ 2 + 1) * (1 / x)
Rewriting:
(f * g) (x) = ((x ^ 2 + 1) / x)
Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
We have then:
All reals except number 0
Answer:
b. all real numbers, except 0
