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3 years ago

Find the area of a right triangle with a hypotenuse of 5 inches and a leg of 3 inches. A) 6 in2

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

7 0

The answer is c because base times height over 2

Alex787 [66]3 years ago

4 0

The answer is C!! Base times height divided by 2

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Find all real solutions and show work: 2x^3-3x^2+18x-27=0

Amiraneli [1.4K]

Given:

The given equation is

$2x^3-3x^2+18x-27=0$

To find:

All the real solutions.

Solution:

We have,

$2x^3-3x^2+18x-27=0$

It can be written as

$x^2(2x-3)+9(2x-3)=0$

$(2x-3)(x^2+9)=0$

Using zero product property, we get

$(2x-3)=0$ and $(x^2+9)=0$

$2x=3$ and $x^2=-9$

$x=\dfrac{3}{2}$ and $x=\pm\sqrt{-9}$

We know that $x=\pm\sqrt{-9}$ is an imaginary number because there is a negative sign under the square root.

Therefore, $x=\dfrac{3}{2}$ is the only real solution of the given equation.

5 0

3 years ago

ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (

harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

See the image in the attachment for the referred diagram.

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

This implies that:

AC/BC = EC/DC = AE/DB

Given:

$EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm$

a. Find the length of AE:

EC/DC = AE/DB

Plug in the values

$\frac{8.1}{5.4} = \frac{AE}{2.6}$

Cross multiply

$5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06$

Divide both sides by 5.4

$AE = \frac{21.06}{5.4} = 3.9 $ cm$

b. Find the length of AB:

$AB = AC - BC$

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

Plug in the values

$\frac{6.15}{BC} = \frac{8.1}{5.4}$

Cross multiply

$BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1$

Thus:

$AB = AC - BC$

Substitute

$AB = 6.15 - 4.1\\\\AB = 2.05 $ cm$

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

Learn more here:

brainly.com/question/14327552

3 0

2 years ago

5*45+6856x=8x+65x+76x

Brut [27]

Answer:

0.033547 I think

Step-by-step explanation:

4 0

3 years ago

Three of exterior angle of n-sided polygon are 50° each two of it's interior angle are 127° and 135° and the remaining interior

irga5000 [103]

Answer:

The value of n is 21.

Step-by-step explanation:

We are given that three of the exterior angle of the n-sided polygon are 50° each two of its interior angle are 127° and 135° and the remaining interior angle are 173 each.

As we know that the sum of all exterior angles of the polygon is 360°. Also, the number of remaining interior angles will be (n - 5).

And, the exterior angle = 180° - the interior angle.

So, according to the question;

$(3 \times 50) + (180-127) + (180 - 135) + (n - 5)\times (180-173) =360$

150 + 53 + 45 + 7(n - 5) = 360

248 + 7n - 35 = 360

213 + 7n = 360

7n = 360 - 213

7n = 147

n = $\frac{147}{7}$

n = 21

Hence, the value of n is 21 and this is a 21-sided polygon.

4 0

3 years ago

Evaluate x2 + y3. If x =2 and y=1/4. Write your answer in simplest form. I need it now!

mart [117]

If x equals 2 and y equals 1/4 , the equation is 2 • 2 + 1/4 • 3
and that equals 4.75

8 0

3 years ago

Read 2 more answers