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olga nikolaevna [1]
3 years ago
11

If the revenue for the week is $2000 and the labor cost consists of two workers earning eight dollars per hour who work 40 hours

each what is labor cost as a percentage of revenue
Mathematics
1 answer:
arsen [322]3 years ago
8 0
To find the cost of labor for one worker, you multiply the wage by the number of hours worked. 

40 * 8 = 320

Because there are two workers, now you double it. 

320 * 2 = 640

To find the percentage of the revenue that this is, you do the labor cost divided by the revenue. 

640 / 2000 = 0.32

Move the decimal two places to the right to get the percentage. 

0.32 = 32%

The labor cost is 32% of the revenue. 
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The measure of first angle is 34 degrees and measure of second angle is 56 degrees

<em><u>Solution:</u></em>

Given that, the exterior sides of two adjacent angles make a right angle

Therefore, these adjacent angles forms 90 degrees

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The first angle has a measure that is six more than half the second

Therefore,

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Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

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What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

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Step-by-step explanation:

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Read 2 more answers
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