3 years ago

Ignore the answer I chose it didn't let me click off of it

Mathematics

2 answers:

elena-s [515]3 years ago

5 0

Pretty sure it would be d

lions [1.4K]3 years ago

3 0

Answer:

d i think

Step-by-step explanation:

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zavuch27 [327]

Answer: $\bold{x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}}$

<u>Step-by-step explanation:</u>

The formula for factoring a cubic is:

a³ + b³ = (a + b)(a² - ab + b²)

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To find the zeros, set each factor equal to zero and solve.

0 = x + 3 0 = x² - 3x + 9

-3 = x use quadratic formula

$x^2-3x+9\quad \rightarrow \quad a=1, b=-3, c=9\\\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(1)(9)}}{2(1)}\\\\\\x=\dfrac{3\pm\sqrt{9-36}}{2}\\\\\\x=\dfrac{3\pm\sqrt{-27}}{2}\\\\\\x=\dfrac{3\pm3i\sqrt{3}}{2}$

Answer:

$x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}$

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3 years ago

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