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madam [21]
2 years ago
9

Find the radius of a circle whose circumference is 9pie

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

Answer:

1.4 (rounded to the nearest tenth)

1.43 (rounded to the nearest hundredths)

1.432 (rounded to the nearest thousandths)

Step-by-step explanation:

C=2 π r

C/2 π = 9/2 * π = (depends what is is rounded to really)

Nookie1986 [14]2 years ago
6 0
Download Socratic it will help you!
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Can someone please help me thanks :)
Dmitrij [34]
29 degrees. You can just add 12 and 17 to find this, since the 12 is negative
7 0
3 years ago
If x = -4, calculate 2x squared - 5
Varvara68 [4.7K]
You just substitute the value of x in the given equation:


f(x) = 2x^2 - 5

f(-4) = 2 (-4)^2 -5 = 27

f(x) : a name given to the equation
f(-4): refer to the equation when the value of the independent variable x has the value between the brackets.
5 0
3 years ago
Given: ΔXYZ AB is a midsegment parallel to XY. The slope of AB is 2 3 . What is the slope of XY?
stich3 [128]
The slope of XY is the same as the slope of AB because XY is parallel to AB. Parallel lines have the same slope. 
5 0
3 years ago
Read 2 more answers
Evaluate the expression when <br> a = -4 and x=5.<br><br> -5a +x
bonufazy [111]

Answer:

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!! Find the fifth roots of 243(cos 240° + i sin 240°).
Snowcat [4.5K]

Answer:

<h2>3(cos 336 + i sin 336)</h2>

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos  Ф  + i sin  Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336)

6 0
2 years ago
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