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OleMash [197]
2 years ago
9

Which of the following expressions are equivalent to -19/8 x(-50)

Mathematics
1 answer:
dmitriy555 [2]2 years ago
5 0

1. Move the negative sign to the left.

-
\frac{19}{8}X*-50

2. Use this rule: \frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}

-\frac{19x*-50}{8}

3. Simplify -  \frac{-950x}{8}

4. Move the negative sign to the left.

-(-950x/8)

5. Simplify 950x/8 to 475x/4

6. Remove parentheses.

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Reggie will finance a car with a sticker price of $9,250. he pays $1,500 down payment he finances the car and makes 48 monthly p
Minchanka [31]

Answer: Reggie will end up paying $9900 for the car.

Step-by-step explanation:

Down-payment = $1500

48 monthly payments x $175/month = $8400

Total cost = $1500 + $8400 = $9900

5 0
4 years ago
Can you pls helplpl me pls
topjm [15]
The answer is B. I hope this helps
7 0
3 years ago
The questions are in the images pls answer all or your answer will be deleted because this is for a lot of points and im losing
PilotLPTM [1.2K]

1)

x + 2y = 21

+ -x + 3y = 29

--------------------------

5y = 50

y = 10

x + 2(10) =21

x = 1

2)

6x + 6y = 30

+ 15x - 6y = 12

-------------------------------

21x = 42

x = 2

6(2) + 6y = 30

6y = 18

y = 3

7 0
3 years ago
Is -8 - 2(3+2n)+7n equivalent to -30 - 13n​
soldi70 [24.7K]

Answer:

The terms are not equivalent

Step-by-step explanation:

-8 - 2(3+2n)+7n

Distribute the 2

-8 -6-4n+7n

Combine like terms

-14 +3n

That is not equal to -30 -13n

The terms are not equivalent

4 0
3 years ago
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0
3 years ago
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