(1,-10)
the 10 must be negative
reason why the others dont work:
(1,10) too positive, the other two start negative, no way is it going to be way up here
(10,1) still too high
(-1,10) then again, too high
Presumably we're being asked for the line which passes through (3,5) and (-1,5) which is simply
Answer:
1) Bigger sector = 168.8pi
1) Smaller sector = 56.3pi
2) Bigger sector = 529.9
3) Smaller sector = 176.6
Step-by-step explanation:
1) Bigger sector =
×pi×15×15
= 168.75pi
1) Smaller sector =
×pi×15×15
=
×pi×15×15
= 56.25pi
2) Bigger sector =
×3.14×15×15
= 529.875
2) Smaller sector =
×3.14×15×15
=
×3.14×15×15
= 176.625
Add digit by digit, from the right, just like any number, except that if it adds to 2, then put a zero and carry one (instead of carrying when it adds to 10 or more).
Example: < means carry, decimal equivalent for checking
1011+1111
1 0 1 1 (8+2+1=11)
+ 1 1 1 1 (8+4+2+1=15)
---<---<----<----<----
1 1 0 1 0 (16+8+2=26)
Proceeding similarly,
a. 10101111+11011011 = 110001010 (394)
b. 10010111+11111111 = 110010110 (406)
c. 01110101+10101100 = 10010001 (289)
Answer: 0.01
Step-by-step explanation:
Let the events are :
C = paving stones found to be cracked.
D = paving stones found to be discolored.
Given : Total stones : T = 600 (i)
C = 15
D= 27
C'∩D'= 564 (ii)
Since C'∩D' = (C∪D)' = T- C∪D (iii)
From (i) , (ii)and (ii) , we have
564 = 600- C∪D
⇒ C∪D=600- 564= 36
Formula : C∩D= C+D- C∪D
Put values , we get
C∩D= 15+27-36=6
Now ,
![P(C\cap D)=\dfrac{C\cap D}{T}=\dfrac{6}{600}=0.01](https://tex.z-dn.net/?f=P%28C%5Ccap%20D%29%3D%5Cdfrac%7BC%5Ccap%20D%7D%7BT%7D%3D%5Cdfrac%7B6%7D%7B600%7D%3D0.01)
The probability that it is both cracked and distorted is 0.01.