Question

Hey can you please help me posted picture of question

Answer 1

The solutions to the given quadratic equation can be determined using quadratic formula.

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b =coefficient of x term = -2
a = coefficient of squared term = 1
c = constant term = 10

Using the values in the above formula we get:

$x= \frac{2+- \sqrt{4-4(1)(10)} }{2(1)} \\ \\ x= \frac{2+- \sqrt{-36} }{2} \\ \\ x= \frac{2+-6i}{2} \\ \\ x=1+3i, x=1-3i$

So the correct answer to this question is option A