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2 years ago

I need this ASAP MY TEACHER KEEPS CONTACTING ME PLZ HELP Combine like terms: 9x+8y-4x-2y9x+8y−4x−2y

Mathematics

2 answers:

adelina 88 [10]2 years ago

8 0

Answer:

If the expression is 2y+9x the answer is: 10x+12y

If the expression is 2y-9x the answer is -8x+12y

Step-by-step explanation:

You would combine all your x values:-4,9,9,-4 and that equals 10 then you would add your variable, so your x value is 10x.

You would then combine all your y values: 8,-2,8,-2, and that equals 12, then you would add your variable, so your y value is 12y.

RUDIKE [14]2 years ago

5 0

Answer:

x+14y-18xy

Step-by-step explanation:

1) Multiply terms if needed.

2) Group your terms by variables. (x with x, y with y, xy with xy, etc.)

3) Add like terms (terms with same variables)

This problem will look like:

Step one: take the term "-2y9x" and multiply to creat one term (You have to remember PEMDAS with these problems. Look it up if you don't know what it is :) ) You should come up with -18yx for this term.

Step two: Organizing terms ---> 9x-4x-4x+8y+8y-2y-18xy

Step three: Take your like terms and add them together. Your answer should end up being x+14y-18xy

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2 years ago

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Answer:

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Step-by-step explanation:

A prism's surface has 2 triangles & 3 rectangles.

In both the triangles , length of :

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2 years ago

Oh no! Thomas is lost in the GGBL building after an exam, and trying to get out. Thereare four identical hallways leading away f

Brums [2.3K]

Answer:

Check the explanation

Step-by-step explanation:

Since each and every one of the 4 hallways is equally likely then

$P(H1)=1/4P(H2)=1/2P(H3)=1/4$

Now, if he chooses H1 he escapes after 12 minutes then

$E(T|H1)=12$

If he chooses H2 then he wastes 10 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H2)=10+E(T)$

Analogously, if he chooses H3 then he wastes 40 minutes and then he is again in the same starting

position so he expects to escape in E(T) minutes, then

$E(T|H3)=40+E(T)$

Therefore

$E(T) = E(T|H1)P(H1) + E(T|H2)P(H2) + E(T H3)P(H3) = (12) + (E(T) +10) + (E(T) + 40) = 3+ *E(T)+5+ 10 = E(T) +18 CON A'$

So we have

$E(T) = E(T) + 18 E(T) = 18 E(T) = 4(18) = 72$

Therefore he is expected to escape in 72 minutes

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3 years ago

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2 years ago

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IrinaVladis [17]

Answer: 17

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2 years ago