What velocity will a freefalling object have after falling 80 meters

Physics

1 answer:

vovangra [49]3 years ago

6 0

Answer:

129.96

At a Gravitational acceleration of 32.17405 ( which is the normal rate for a freefall) you will geta velocity of 129.96 and the time of fall will be 4.039 seconds from 80 meters.

Why is the weight of a free falling body zero? It is not, an object in free fall will still have a weight, governed by the equation W = mg, where W is the object's weight, m is the object's mass, and g is acceleration due to gravity. Weight, however, has no effect on an objects free falling speed, two identically shaped objects weighing a different amount will hit the ground at the same time.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

You might be interested in

A ball is kicked off of a roof at 23 m/s [R 25° U]. What is the height of

Ymorist [56]

Answer:

Explanation:

Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:

$v_{0y}=v_0sin\theta$ and filling in:

$v_{0y}=23sin(25)$ which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:

$v_{0y}=9.7m/s$

a = -9.8 m/s/s

t = 2.8 seconds

Δx = ?? m

The one-dimensional motion equation that utilizes all of these variables is

Δx = $v_0t+\frac{1}{2}at^2$ and filling in:

Δx = $9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2$ I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have

Δx = 27 + $\frac{1}{2}(-9.8)(2.8)^2$ and then to the right of the + sign and to 2 significant digits we have

Δx = 27 - 38 so

Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.

6 0

3 years ago

Suppose that the speed of yellow visible light in a certain transparent medium is 2.01* 105 km/s. What, approximately, is the in

True [87]

Answer:

$1.50$