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Elodia [21]
3 years ago
13

If you take a deep breath of air, you can float more easily in water because you have _____.

Physics
2 answers:
Leni [432]3 years ago
6 0

Answer:

the answer is c

Kamila [148]3 years ago
3 0
C. increased your buoyant force
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A bus starts to move from rest. if its velocity becomes 90 km per hour after 8s second. calculate acceleraton​
topjm [15]

90 km per hour = 25 metres per second

a=\frac{v-u}{t}

a=\frac{25-0}{8}

a=3,13m/s^2

7 0
3 years ago
How do fission nuclear reactions differ from fusion nuclear reactions?
Serhud [2]
The path of the raction occurs on the basis of mass of the nuclei involved in reaction.
In case of nuclear fusion, two or more nuclei having less mass fuse(combine, join) together to form a new nuclei(heavier mass but it is relatively stable). During fusion, matter is not conserved because some of the matter is converted into energy(light). This reaction evolves a huge amount of energy and there comes Einstein's famous Energy-mass equivalence formula E=mc^2! :D. The nuclear reaction occuring in stars(including our sun ) is "fusion".

Fission occurs with heavier nuclei such as that of Uranium-235. Which splits into smaller subatomic particles like gamma, neutrons and enormous amount of energy.
Both, Fission and Fusion releases enormous amount of energy and modern nuclear weapons works on the principle of nuclear fission.

6 0
3 years ago
Read 2 more answers
A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

T = tension

Put the value into the formula

v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}

v =519.61\ m/s

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
3 years ago
The force required to maintain an object at a constant speed in free space is equal to __________
rusak2 [61]
The correct answer is: zero.
8 0
3 years ago
Two charges, qA and qB, are separated by a distance, d, and exert a force, F, on each other. Analyze Coulomb's law and answer th
maria [59]

Answer: a. F doubled

b. F reduced by one-quarter i.e

1/4*(F)

c. 1/9*(F)

d. F increased by a factor of 4 i.e 4*F

e. F reduces 3/4*(F)

Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is

F = k*(qA*qB)/d²

a. If qA is doubled therefore the force is doubled since they are directly proportional.

b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4

Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.

c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9

d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4

e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,

3/4*F

6 0
4 years ago
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