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First thing plot a right angle with angle of elevation of 35degrees as shown in figure then use SOHCAHTOA.
Ay/Helicopter = sin 35
Ay = 86 sin 35 = 36.8237
Ax/Helicopter = cos 35
Ax = 86 cos 35 = 77.7175
Note: I ignore the negative signs coz they signify direction
Machine C. Machine A has an efficiency of 250/1000 = 0.25 = 25%, Machine B's efficiency is 350/500 = 0.7 = 70% and Machine C has an efficiency of 150/200 = 0.75 = 75%.
The volume of a cube is given by:

where L is the measure of each side (which corresponds to its width, since all sides of a cube are equal).
Plugging the data of the problem, L=32.1 cm, inside the equation, we find the volume:

Answer:
x = 2.69 cm
Explanation:
We are given ;
Density of oil; ρ_oil = 924 kg/m³
Density of wood; ρ_wood = 970 kg/m³
h = 3.79cm
Density of water ( ρ_water) has a constant value of 1000 kg/m³
At equilibrium position, we have;
ρ_wood•g•h - ρ_oil•g•(h - x) - ρ_water•g•x = 0
This is because the density of oil is lower than that of water while density of wood is higher than that of oil but lower than that of water.
x is the distance below the interface between the two liquids is the bottom of the block.
Thus, let's make x the subject;
x = [(ρ_wood - ρ_oil)/(ρ_water - ρ_oil)] x h
Plugging in the relevant values to get ;
x = [(970 - 924)/(1000 - 924)] x 3.79
x = (54/76) x 3.79 = 2.69cm