Answer:
A) 2.02 standard deviations from 600 - a win
B) The last interval was a close call.
Explanation:
n = 2300
p = 0.47, q = 1-p = 0.53
μ = np = 1081
σ = √(npq) = 23.94
Z.025 = 1.96
B) Finding both confidence interval:
Confidence Interval = (μ-1.96(23.94)/√2300, μ+1.96(23.94)/√2300)
= (1081 - 0.978, 1081 + 0.978)
= (1080.022, 1081.978)
(1080-600)/23.94 = 2.02 standard deviations from 600 - a win
B)
AS above
n=450, p=.54, q=.46
μ=np=243, σ=√(npq)=10.6
confidence interval (243-1.96(10.6)/√450 , 243+1.96(10.6)/√450)
= 243-.98, 243+.98) = (242.0, 243.98)
(244-225)/10.6=1.8 standard deviations from win
Answer: Wilson suggested 14 points on which a lasting peace in Europe should be established.
Explanation:
In this pattern, the United States represented a good landmark among the warring European countries. The 14 points Wilson presented to Congress should establish world peace. They further implied political and other independence of individual countries. Wilson called for a united one to end future conflicts. He also called for free trade. Many welcomed Wilson's proposals with approval. However, some viewed the president's steps as idealizing. Furthermore, at a peace conference that ended World War I, the victorious nations demanded that the US president be more rigorous with Germany. The president did not take such a harsh stance on Germany, and France demanded that Germany be severely punished for World War I.
Political- freedom of press, rule of law, and levels of bureaucracy, and corruption economic- unemployment and labor supply. social- cultural
