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Black_prince [1.1K]
2 years ago
13

Jamall paid the rent well past the due date for the month of April May and June as a result he had been charge a total of $75 as

a late fee how much does he have pay as late fee per month
Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

Answer:

its In “Growing Up: Key Moments,” which piece of evidence best supports the author’s idea that challenging moments help people learn as they grow up?

Step-by-step explanation:

bc ez ez e yba better then aut

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3x+2=17

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You deposit $3000 into an account which earns 5.1% interest per year, compounded annually. your friend simultaneously deposits $
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for 3000 friend it is in 2 years


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1/2

please mark me brainliest

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Who are the two groups of people Ishmael faces danger from?
nikdorinn [45]

Answer:

The two groups of people Ismael faces danger from were the group of muscular men with machetes and crowded village where they stopped on their way.

3 0
3 years ago
Graph the functions on the same coordinate axis. {f(x)=−2x+1g(x)=x2−2x−3
NikAS [45]

Answer:

(2,-3) and (-2,5)

Step-by-step explanation:

Let us graph the two equations one by one.

1. f(x)=-2x+1

If we compare this equation with the slope intercept form of a line which is given as

y=mx+c

we see that m = -1 and c =1

Hence the slope of the line is -2 and the y intercept is 1. Hence one point through which it is passing is (0,1) .

Let us find another point by putting x = 1 and solving it for y

y=-2(1)+1

y=-2+1 = -1

Let us find another point by putting x = 2 and solving it for y

y=-2(2)+1

y=-4+1 = -3

Hence the another point will be (2,-3)

Let us find another point by putting x = -2 and solving it for y

y=-2(-2)+1

y=+1 = 5

Hence the another point will be (-2,5)

Now we have two points (0,1) ,(1,-1) ,  (2,-3) and (-2,5) we joint them on line to obtain our line  

2.

g(x)=y=x^2-2x-3

y=x^2-2x+1-1-3

y=(x-1)^2-4

(y+4)=(x-1)^2

It represents the parabola opening upward with vertices (1,-4)

Let us mark few coordinates so that we may graph the parabola.

i) x=0 ; y=y=(0)^2-2(0)-3=0-0-3=-3 ; (0,-3)

ii)x=-1 ; y=(-1)^2-2(-1)-3=1+2-3=0 ; (-1,0)

iii) x=2 ; y=(2)^2-2(2)-3 = 4-4-3 =-3 ;(2,-3)

iii) x=1 ; y=(1)^2-2(1)-3 = 1-2-3 =-4  ;(1,-4)

iii) x=-2 ; y=(-2)^2-2(-2)-3 = 4+4-3 =5  ;(-2,5)

Now we plot them on coordinate axis and line them to form our parabola

When we plot them we see that we have two coordinates (2,-3) and (-2,5) are common , on which our graphs are intersecting. These coordinates are solution to the two graphs.

3 0
4 years ago
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