The infinite geometric series is converges if |r| < 1.
We have r=1/6 < 1, therefore our infinite geometric series is converges.
The sum S of an infinite geometric series with |r| < 1 is given by the formula :
We have:
substitute:
Answer: d. Converges, 504.
i think the answer is x ≤ -8
Answer:
x = 1 and 10
Step-by-step explanation:
Given the equation \sqrt{-x+26}=x-6, we are to find the value of x
Take the square of both sides
(\sqrt{-x+26})²= (x-6)²
-x+26 = (x-6)²
Expand the parenthesis
-x+26 = x²-12x+36
x²-12x+36+x-26 = 0
x²-11x+10 = 0
x²-10x-x +10 = 0
x(x-10) -1()-10) = 0
(x-1)(x-10) = 0
x - 1 =0 and x - 10 = 0
x = 1 and 10
Hence the value of x is 1 and 10
