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Rudiy27
3 years ago
8

The weight of an object on a particular scale is 175.2 lbs. The measured weight may vary from the actual weight by at most 0.1 l

bs. What is the range of actual weights of the object?
Mathematics
2 answers:
larisa86 [58]3 years ago
7 0

Answer:

It’s A

Step-by-step explanation:

snow_lady [41]3 years ago
5 0
Either 175.25 ( 175.2 + 0.1/2) or 175.15 ( 175.2 - 0.1/2) ----------> Range. 175.15 < weight < 175.25
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Please help right away.
Travka [436]

\sum\limits_{k=1}^{\infty}420\left(\dfrac{1}{6}\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r=1/6 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

S=\dfrac{a_1}{1-r}

We have:

a_1=420\left(\dfrac{1}{6}\right)^{1-1}=420\left(\dfrac{1}{6}\right)^0=420\\\\r=\dfrac{1}{6}

substitute:

S=\dfrac{420}{1-\frac{1}{6}}=\dfrac{420}{\frac{5}{6}}=420\cdot\dfrac{6}{5}=84\cdot6=504

Answer: d. Converges, 504.

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3 years ago
If one rectangular solid with dimensions of 6 x 6 x10 millimeters is stacked on top of an identical rectangular solid so that th
ollegr [7]

Answer: 720

Step-by-step explanation: took the test

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Arte-miy333 [17]

Answer:

\frac{(x - 2)(x + 2)}{x - 8}

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3 years ago
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Solve the inequality. x – 1 ≤ – 9
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7 0
3 years ago
\sqrt{-x+26}=x-6 −x+26=x−6
schepotkina [342]

Answer:

x = 1 and 10

Step-by-step explanation:

Given the equation \sqrt{-x+26}=x-6, we are to find the value of x

Take the square of both sides

(\sqrt{-x+26})²= (x-6)²

-x+26 = (x-6)²

Expand the parenthesis

-x+26 = x²-12x+36

x²-12x+36+x-26 = 0

x²-11x+10 = 0

x²-10x-x +10 = 0

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(x-1)(x-10) = 0

x - 1 =0 and x - 10 = 0

x = 1 and 10

Hence the value of x is 1 and 10

7 0
3 years ago
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