The weight of an object on a particular scale is 175.2 lbs. The measured weight may vary from the actual weight by at most 0.1 l
2 answers:
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Answer:
0.4
Step-by-step explanation:
Given:-
- The uniform distribution parameters are as follows:
a = $10,000 b = $15,000
Find:-
Suppose you bid $12,000. What is the probability that your bid will be accepted?
Solution:-
- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].
X ~ U(10,000 , 15,000)
- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:
Pmf = 1 / ( b - a )
Pmf = 1 / ( 15,000 - 10,000 )
Pmf = 1 / ( 5,000 )
Answer:
<h2>i) 3</h2><h2>ii) 5</h2>Step-by-step explanation:
Let H be the set of students who play Hokey
V be the set of students who play Volleyball
S be the set of students who play Soccer
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card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]
= 73 - [50 + (58-50) + (62-50)]
= 73 - [50 + 8 + 12]
= 73 - 70
= 3
………………………………………………
Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]
= 100 - 95
= 5
…………………
<u><em>Note</em></u> :
A Venn diagram might be helpful in such case.
