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Murljashka [212]
3 years ago
9

Which of the following would cause electromagnetic induction?

Physics
1 answer:
koban [17]3 years ago
4 0

A flashlight is charged by shaking an internal magnet back and forth through coiled wires.

Explanation:

Charging a flashlight by shaking an internal magnet back and forth through coiled wires can cause electromagnetic induction to occur. The wire is in the vicinity of changing magnetic fields.

  • Electromagnetic induction or induction is the production of electromotive force(EMF) by varying the magnetic field in an electrical conductor.
  • The wire serves as the electrical conductor.
  • As the magnetic flux on it changes, the electromotive force is then produced.

Learn more:

Electromagnetic spectrum brainly.com/question/9184100

#learnwithBrainly

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4. Find the uniform acceleration that causes a car’s velocity to change from 32m/s to
GrogVix [38]

Answer:

a=8\ m/sec^2

Explanation:

we know that

The formula  to calculate the acceleration is

a=\frac{V_2-V_1}{t}

we have

V_2=96\ m/sec

V_1=32\ m/sec

t=8\ sec

substitute

a=\frac{96-32}{8}

a=8\ m/sec^2

4 0
4 years ago
Water behind a dam has a certain amount of stored energy that can be released as the water falls over the top of the dam. It may
Tpy6a [65]

Answer:

The answer is potential energy

Explanation:

The potential energy is the energy possessed by a body by virtue of it position

For example the water at the top of the dam is being held at a height h above the bottom of the dam

Then the potential energy

PE= weight of the water* the height

PE= m*g*h

8 0
4 years ago
How does walking rather than riding in a car save resources
Lorico [155]
Because you are not using gas oil etc, in other words you are saving fossil fuels by walking instead of driving a car
also could I get brainliest plz
5 0
3 years ago
Read 2 more answers
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
rosijanka [135]

Answer:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

Explanation:

For this case we know that the initial velocity is given by:

v_i = 7 \frac{m}{s}

The final velocity on this case is given by:

v_f = 13 \frac{m}{s}

And we know that it takes 8 seconds to go from 7m/s to 13m/s. We can use the following kinematic formula in order to find the acceleration during the first interval:

v_f = v_i +at

If we solve for the acceleration we got:

a = \frac{v_f -v_i}{t} = \frac{13 m/s -7 m/s}{8 s}= 0.75 \frac{m}{s^2}

So for the other traject we assume that the acceleration is constant and the train travels for 16 s. The initial velocity on this case would be 13m/s from the first interval and we can find the final velocity with the following formula:

v_f = v_ i +a t

And if we replace we got:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

5 0
4 years ago
A baseball is batted from a height of 1.09 m with a speed of
kobusy [5.1K]

(a) The horizontal and vertical components of the ball’s initial velocity is 37.8 m/s and 12.14 m/s respectively.

(b) The maximum height above the ground reached by the ball is 8.6 m.

(c) The distance off course the ball would be carried is 0.38 m.

(d) The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

<h3>Horizontal and vertical components of the ball's velocity</h3>

Vx = Vcosθ

Vx = 39.7 x cos(17.8)

Vx = 37.8 m/s

Vy = Vsin(θ)

Vy = 39.7 x sin(17.8)

Vy = 12.14 m/s

<h3>Maximum height reached by the ball</h3>

H = \frac{v^2 sin^2(\theta)}{2g} \\\\H = \frac{(39.7)^2 \times (sin17.8)^2}{2(9.8)} \\\\H = 7.51 \ m

Maximum height above ground = 7.51 + 1.09 = 8.6 m

<h3>Distance off course after 2 second </h3>

Upward speed of the ball after 2 seconds, V = V₀y - gt

Vy = 12.14 - (2x 9.8)

Vy = - 7.46 m/s

Horizontal velocity will be constant = 37.8 m/s

Resultant speed of the ball after 2 seconds = √(Vy² + Vx²)

V = \sqrt{(-7.46)^2 + (37.8)^2} \\\\V = 38.53 \ m/s

<h3>Resultant speed of the ball and crosswind</h3>

V = \sqrt{38.52^2 + 4^2} \\\\V = 38.72 \ m/s

<h3>Distance off course the ball would be carried</h3>

d = Δvt = (38.72 - 38.53) x 2

d = 0.38 m

The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

Learn more about projectiles here: brainly.com/question/11049671

5 0
2 years ago
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