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alex41 [277]
3 years ago
15

Which statements best describe the motion of Car A and Car B? Check all that apply. Car A and Car B are both moving toward the o

rigin. Car A and Car B are moving in opposite directions. Car A is moving faster than Car B. Car A and Car B started at the same location. Car A and Car B pass each other at the crossover point on the graph.
Physics
2 answers:
Lera25 [3.4K]3 years ago
6 0

Answer: car b

Explanation:

mojhsa [17]3 years ago
3 0

Answer:

Car A and Car B pass each other at the crossover point on the graph

.Car A and Car B are moving in opposite directions.

Car A is moving faster than Car B. these are the ansers

Explanation:

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If the speed is higher than the orbital velocity, but not high enough to leave Earth altogether (lower than the escape velocity), it will continue revolving around Earth along an elliptical orbit. (D) for example horizontal speed of 7,300 to approximately 10,000 m/s for Earth.
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A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe
Alchen [17]
A)
2revs in 0.08s
   so in 1s thats 25revs
therefore thats <u>50π radians</u> in one second

b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
and v=rω where r is in meters;
v=0.3x157.079
<u>v=47.123ms^-1</u>

c)
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3 years ago
PLEASE HELP I WILL GOVE BRAINLIEST TO FIRST CORRECT ANSWER!!!!!
Dmitrij [34]
Answer is C is the correct answer
8 0
3 years ago
A circular loop of wire 75 mm in radius carries a current of 113 A. Find the (a) magnetic field strength and (b) energy density
Roman55 [17]

The magnetic field strength is 9.47 ×10⁻⁴ T

The energy density at the center of the loop is 0.36 J/m³

<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

B = \frac{\mu_{0} I}{2R}

Where  B is the magnetic field strength

\mu_{0} is the permeability of free space (\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})

I is the current

and R is the radius

From the give information,

R = 75 \ mm= 75 \times 10^{-3} \ m

and I = 113 \ A

Putting the parameters into the formula, we get

B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }

B = 9.47 \times 10^{-4} \ T

Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

u_{B}  = \frac{B^{2} }{2\mu_{0} }

Where u_{B} is the energy density

Then,

u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }

u_{B} = 0.36 \ J/m^{3}

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

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Answer: A

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