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2 years ago

15

In January,the low temperature in Denver was -12 degrees,and the low temperature in Chicago was -17 degree.which statement is tr

ue

1 answer:

nadezda [96]2 years ago

8 0

The answer is C ( ask why if you want)

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The Pythagorean Theorem can be used to find the missing side length of a triangle when two other side lengths are known.

lubasha [3.4K]

Answer:

The value of b is 21

Step-by-step explanation:

29=√20^2+b^2

or, 29=√400+b^2

or, 841=400+b^2

or, 841-400=b^2

or, √441=b

b=21

5 0

1 year ago

Please help anyone

olya-2409 [2.1K]

There is no picture of the graph

3 0

2 years ago

Factor 16x4 - 4y2<br><br> A) (x + 4y)(x - 4y)<br> B) 4(2x2 + y)(2x2 - y)

Alex73 [517]

Step-by-step explanation:

$16 {x}^{4} - 4 {y}^{2} \\ {4}^{2} {x}^{4} - {2}^{2} {y}^{2} \\ {4}^{2} {x}^{2} \times {x}^{2} - {2}^{2} {y}^{2} \\ (4 {x}^{2} - 2y)(4 {x}^{2} - 2y)$

6 0

2 years ago

Read 2 more answers

I need an explanation for the problem 4v2=-12v-9. I don't understand why it factors into 4v+3 and 4v+3

kirza4 [7]

Answer:

The factors are $2v+3,2v+3$ .

The factors are not $4v+3,4v+3$

Step-by-step explanation:

Equation is $4v^2=-12v-9$ .

This equation can be written as follows:

$4v^2+12v+9=0$

Here,

$12v=6v+6v$

Therefore,

$4v^2+6v+6v+9=0\\2v(2v+3)+3(2v+3)=0\\(2v+3)(2v+3)=0$

So, the factors are $2v+3,2v+3$ .

The factors are not $4v+3,4v+3$

7 0

2 years ago

I just need no. a please help me to prove this.

OleMash [197]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π and cos A = cos B · cos C

scratchwork:

A + B + C = π

A = π - (B + C)

cos A = cos [π - (B + C)] Apply cos

= - cos (B + C) Simplify

= -(cos B · cos C - sin B · sin C) Sum Identity

= sin B · sin C - cos B · cos C Simplify

cos B · cos C = sin B · sin C - cos B · cos C Substitution

2cos B · cos C = sin B · sin C Addition

$2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}$ Division

2 = tan B · tan C

$\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}$

<u>Proof LHS → RHS</u>

Given: A + B + C = π

Subtraction: A = π - (B + C)

Apply tan: tan A = tan(π - (B + C))

Simplify: = - tan (B + C)

$\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)$

Substitution: = -(tan B + tan C)/(1 - 2)

Simplify: = -(tan B + tan C)/-1

= tan B + tan C

LHS = RHS: tan B + tan C = tan B + tan C $\checkmark$

5 0

2 years ago