Answer:
I think the an 8..good luck
Hey friend, hope I can assist you!
I will solve by elimination <3.
Multiply 3x - 7y = 2 by 2: 6x - 14y = 4
6x - 14y = 4
6x - 9y = 9
5y = 5
Now we have
6x - 14y = 4
5y = 5
Now we want to solve 5y = 5 for y
So simply divide both sides by 5.
5y/5 = 5/5
This gives us one or in other words, y = 1.
Now we want to plug y = 1 into 6x - 14y = 4
So 6x - 14 * 1 = 4
This gives us
6x - 14 = 4
Now add 14 to both sides.
6x - 14 + 14 = 4 + 14
6x = 18
Now divide both sides by 6
6x/6 = 18/6
This gives us 3 so x = 3
Therefore our solutions to this system of equations would be y = 1 and x = 3
Answer:
Step-by-step explanation:
n = 8
c(n) = -6+5(n - 1)
c(8) = -6+5(8 - 1)
c(8) = -6+5( 7)
c(8) = -6+5(7)
c(8) = -6+35
c(8) = 29
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Here is the series.
-6
-1
4
9
14
19
24
29
<em>The answer is
</em>The reason we get this answer is because when you are converting from exponential form, to radical form you always place the numerator as our constant's exponent in the radical <em>(

is called the radicand because it is located in the radical)</em> and the denominator in front of the radical, where it would be called the index.
<em>Here's what a formula would look like:</em> ![( \sqrt[n]{x} ) ^{q}=x^{ \frac{p}{q} }](https://tex.z-dn.net/?f=%28%20%5Csqrt%5Bn%5D%7Bx%7D%20%29%20%5E%7Bq%7D%3Dx%5E%7B%20%5Cfrac%7Bp%7D%7Bq%7D%20%7D%20)
Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if I can help you further! :D
Whats the problem for this?