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Nata [24]
2 years ago
5

Barry rode his scooter for 24 minutes at a speed of 0.5 miles per minute. How far did he go?

Mathematics
2 answers:
Kaylis [27]2 years ago
8 0
Answer: 12 miles. This is because 24 x 0.5 = 12
guajiro [1.7K]2 years ago
5 0

Answer:

c.12 miles

Step-by-step explanation:

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An 8-inch dinner knife is sitting on a circular plate so that its ends are on the edge of the plate. If the minor arc that is in
ankoles [38]

The diameter of the plate is 9.24 inches

Step-by-step explanation:

Let us consider the radius to be 'r'

Angle = 120°

Chord length = 8 inches

Chord length = 2rsin(θ/2)

8 = 2r sin(120/2)

8 = 2r sin60°

8/2 = r (√3/2)

4/(√3/2) = r

r = 8/√3

r = 8/1.73

r = 4.62 inches

Diameter of the plate = 2(4.62)

= 9.24 inches

The diameter of the plate is 9.24 inches

7 0
3 years ago
If there is 3/4 of pizza and it’s cut into 12/16 and everyone eats 2 slices how many slices are left
dedylja [7]
3/4=12/16 so 0 ? or is it something totally different
3 0
3 years ago
In the barn, there are horses and chickens. There are 11 heads and 32 legs altogether. How many chickens are there?
Masteriza [31]

Answer:

6 Chickens

Step-by-step explanation:

Let  H represent the number of horses and  C represent the number of chickens. Since there are 32 legs altogether this means that on equation to use would be given by:

2C  +  4 H  =  32     (Eq. 1)

Another equation can be made from the fact that there are 11 heads or 11 animals altogether which can be written as:

C  +  H  =  11    (Eq. 2)

From Eq. 2, solve for the number of chickens:

C  +  H  =  11

C   =  11  - H    (Eq. 3)

Substituting Eq. 3 in Eq. 1, the number of horses can be determined:

2 C  +  4 H  =  32

2 ( 11  −  H )  +  4 H  =  32

22   −  2 H  +  4 H  =  32

2H  =  32  − 22

2 H  = 10

H = 5               Eq.4

Putting Eq.4 in Eq.1

2C + 4*5 =  32

2C = 32 - 20

2C = 12

C = 12/2

C = 6

8 0
2 years ago
A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe
djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

\mathbf{h(t) = -16t^2 + 160t}

Differentiate the function with respect to t

\mathbf{h'(t) = -32t + 160}

Set to 0

\mathbf{h'(t) = -32t + 160 = 0}

So, we have:

\mathbf{-32t + 160 = 0}

Collect like terms

\mathbf{-32t =- 160 + 0}

\mathbf{-32t =- 160}

Solve for t

\mathbf{t = \frac{- 160}{-32}}

\mathbf{t = 5}

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0
2 years ago
What kind of sequence is the pattern 1, 6, 7, 13, 20, ...?
AlexFokin [52]

Answer:

The given sequence 6, 7, 13, 20, ... is a recursive sequence

Step-by-step explanation:

As the given sequence is

6, 7, 13, 20, ...

  • It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.

As

d = 7-6=1,  d = 13-7=6

As d is not same. Hence, it cannot be an arithmetic sequence.

  • It also cannot be a geometrical sequence and exponential sequence.

It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.

As

r = 7-6=1,  r = 13-7=6

r = \frac{7}{6},  r = \frac{13}{7}

As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.

So, if we carefully observe, we can determine that:

  • The given sequence 6, 7, 13, 20, ... is a recursive sequence.

Please have a close look that each term is being created by adding the preceding two terms.

For example, the sequence is generated by starting from 1.

     {\displaystyle F_{1}=1

and

     {\displaystyle F_{n}=F_{n-1}+F_{n-2}}

for n > 1.

<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>

<em>Learn more about sequence from brainly.com/question/10986621</em>

<em>#learnwithBrainly</em>

6 0
3 years ago
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