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Alekssandra [29.7K]
3 years ago
13

2.) 3(10x + 9) - 9(3x - 5) SHOW WORK PLEASE

Mathematics
2 answers:
BigorU [14]3 years ago
6 0

Answer:

Let's simplify step-by-step.

3(10x+9)−9(3x−5)

Distribute:

=(3)(10x)+(3)(9)+(−9)(3x)+(−9)(−5)

=30x+27+−27x+45

Combine Like Terms:

=30x+27+−27x+45

=(30x+−27x)+(27+45)

=3x+72

avanturin [10]3 years ago
5 0

Answer:

3x+72

Step-by-step explanation:

Let's first simplify the equation 3(10x+9)−9(3x−5)

You want to distribute first

=(3)(10x)+(3)(9)+(−9)(3x)+(−9)(−5)

=30x+27+−27x+45

And then combine like terms:

=30x+27+−27x+45

=(30x+−27x)+(27+45)

=3x+72 (answer)

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Hi, need help with solving this logarithm.​
vfiekz [6]

Answer:

\log 8 - \log x + 7\log\sqrt x =\log (8x^{\frac{5}{2}})

Step-by-step explanation:

Given

\log 8 - \log x + 7\log\sqrt x

Required

Express as a single expression

We have:

\log 8 - \log x + 7\log\sqrt x

Write 7 as an exponent

\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(\sqrt x)^7

Rewrite as:

\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log(x^{\frac{1}{2}})^7

\log 8 - \log x + 7\log\sqrt x =\log 8 - \log x + \log x^\frac{7}{2}

Apply quotient and product rule of logarithm

\log 8 - \log x + 7\log\sqrt x =\log (\frac{8*x^\frac{7}{2}}{x} )

Apply law of indices

\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7}{2} - 1})

Solve exponent

\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{7-2}{2}})

\log 8 - \log x + 7\log\sqrt x =\log (8*x^{\frac{5}{2}})

\log 8 - \log x + 7\log\sqrt x =\log (8x^{\frac{5}{2}})

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3 years ago
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