Answer:
Step-by-step explanation:
Answer:

Explanation:
All the other expressions can be factorized. Let's see why:
1) 
This is the sum of the cubes, and this can be factorized as follows:

In this case, a=m and b=1, so we can factorize as

2) 
This is the difference between two cubes, and this can be factorized as follows:

In this case, a=m and b=1, so we can factorize as

3) 
This is the difference between two square numbers, and it can be factorized as follows

In this case, a=m and b=1, so we can factorize as

Answer: Approximately normal, because we expect 19.2 successes and 20.8 failures from people in their twenties, and 16.8 and 43.2 from people in their fifties, and all of these counts are at least 10.
Step-by-step explanation:
<h3>
Answer: 7x-7</h3>
===========================================
Work Shown:
(6x-2)-(-x+5)
6x-2+x-5
(6x+x)+(-2-5)
7x-7
When distributing the negative, don't forget to apply the negative to every term inside the parenthesis. So that means -x flips to x, while +5 flips to -5.
Answer:
The area between z = 1.74 and z = 1.25 is of 0.065.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The area between two values of Z is given by the subtraction of the pvalue of the larger value by the smaller.
The area between z = 1.74 and z = 1.25.
This is the pvalue of z = 1.74 subtracted by the pvalue of z = 1.25.
z = 1.74 has a pvalue of 0.959
z = 1.25 has a pvalue of 0.894
0.959 - 0.894 = 0.065
The area between z = 1.74 and z = 1.25 is of 0.065.