Find an equation of the vertical line that passes through (x, y) = (−7, 1).

HURRY PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

frez [133]

Answer:

8

Step-by-step explanation:

It be wayyy to much to put 13 it would make the mean 9 8 is perfect

5 0

3 years ago

What is the approximate age of a woman whose normal systolic pressure measures 125 mm Hg?

sashaice [31]

The approximate age of a woman whose normal systolic pressure measures 125 mm Hg is 31

The function is given as:

$P(A) = 0.006A^2 - 0.02A + 120$

When the normal systolic pressure is 125, it means that:

$P(A) = 125$

So, we have:

$125 = 0.006A^2 - 0.02A + 120$

Subtract 125 from both sides of the equation

$0= 0.006A^2 - 0.02A + 120 -125$

$0= 0.006A^2 - 0.02A - 5$

Rewrite the equation as:

$0.006A^2 - 0.02A - 5 = 0$

Using a graphing calculator, we have:

$A = \{30.58, -27.25\}$

But age cannot be negative.

So, we have:

$A = 30.58$

Approximate

$A =31$

Hence, the age of the woman is 31

Read more about quadratic functions at:

brainly.com/question/11441586

8 0

2 years ago

Read 2 more answers

Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month. During the 12 month period, how many time

kari74 [83]

5 months for it 5 times 250= 1250

7 0

3 years ago

Read 2 more answers

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

$H_0 : \sigma = 10$

$H_1 : \sigma \neq 10$

The test statistics can be computed as follows:

$X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}$

$X^2 = \dfrac{(36 -1)10.1^2 }{10^2}$

$X^2 = \dfrac{(35)102.01 }{100}$

$X^2 = \dfrac{3570.35 }{100}$

$X^2 =35.704$

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703 ( to four decimal places)

Decision Rule : To reject the null hypothesis if P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.