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eduard
3 years ago
7

How to convert a fraction into a mixed number in lowest terms?

Mathematics
2 answers:
blondinia [14]3 years ago
4 0
Ask your self how many times can the top number fit in to the bottom
saveliy_v [14]3 years ago
3 0
Well at first you take the numerator (the top number) and divide it by the denominator (the lower number) that'll give you the whole number. then you would reduce only the fraction. for example lets say that we have 4/8 We know that at the very least since they are both  even numbers we can divide by so so if we do that we have 2/4 oh look, even numbers again and divide both sides by two again and you get 1/2.
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25,-9,18,1 ,-7,-20,10,14,-4,0,12,-14 out the following integers from least to greatest
Trava [24]

Answer:

-20, -14, -9, -7, -4, 0, 1, 10, 12, 14, 18, 25

Step-by-step explanation:

7 0
4 years ago
Find an expression for the nth term (t_n) in each of the following​
Serhud [2]
<h3><u>Answer:</u></h3>

\boxed{\pink{\tt\longmapsto The \ nth \ term \ of \ the \ sequence\ is \ given \ by \frac{1}{n}}}

<h3><u>Step-by-step explanation:</u></h3>

A sequence is given to us is , and we need to find expression for nth term of the sequence. The given sequence is ,

\boxed{\boxed{\blue{\qquad\bf 1 , \dfrac{1}{2},\dfrac{1}{3},\dfrac{1}{4},\dfrac{1}{5},\dfrac{1}{6}}}}

When we flip the numbers , we can clearly see that the number are in Harmonic Progression.

That is when we flip the numbers they are found to be in Arithmetic Progression .

And nth term of an Harmonic Progression is :-

\boxed{\purple{\bf T_{(Harmonic \ Progression)} = \dfrac{1}{a+(n-1)d}}}

Hence here

  • Common difference = 1
  • First term = 1 .

<u>Substituting the respective values,</u>

\bf\implies T_{n}= \dfrac{1}{a+(n-1)d} \\\\\bf\implies T_{n} = \dfrac{1}{1+(n-1)1}\\\\\bf\implies T_n = \dfrac{1}{1+n-1}\\\\\bf\implies\boxed{\red{\bf T_{n}=\dfrac{1}{n}}}

<h3><u>Hence the nth term of the given sequence is given by ¹/n .</u></h3>

3 0
3 years ago
I need help please, I am so confused.​
vazorg [7]

Answer:

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point:  the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward.  As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation:  y=x(x-2)

\implies x(x-2)=0

\implies x=0

\implies (x-2)=0 \implies x=2

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: y=(x-4)(x+5)

\implies (x-4)(x+5)=0

\implies (x-4)=0 \implies  x=4

\implies (x+5)=0 \implies x=-5

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: y=-5x(3-x)

\implies -5x(3-x)=0

\implies -5x=0 \implies x=0

\implies (3-x)=0 \implies x=3

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

4 0
2 years ago
Solve for X. 67 = 18 + X
slavikrds [6]
67=18+x
-18. -18
49=x
8 0
3 years ago
Nine take away three and one-half
DochEvi [55]
5 and 1 half this is the answer my son thought of.
3 0
4 years ago
Read 2 more answers
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