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3 years ago

7

How to convert a fraction into a mixed number in lowest terms?

2 answers:

blondinia [14]3 years ago

4 0

Ask your self how many times can the top number fit in to the bottom

saveliy_v [14]3 years ago

3 0

Well at first you take the numerator (the top number) and divide it by the denominator (the lower number) that'll give you the whole number. then you would reduce only the fraction. for example lets say that we have 4/8 We know that at the very least since they are both even numbers we can divide by so so if we do that we have 2/4 oh look, even numbers again and divide both sides by two again and you get 1/2.

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What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?

ZanzabumX [31]

Answer:

x = $\frac{12+\sqrt{138} }{6}$ and x = $\frac{12-\sqrt{138} }{6}$

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: $x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $x=\frac{-b-\sqrt{b^2-4ac} }{2a}$ .

Here, a = 6, b = -24, and c = 1. Plug these in:

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}$

AND

$x=\frac{-b-\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}$

Thus, the zeroes are: x = $\frac{12+\sqrt{138} }{6}$ and x = $\frac{12-\sqrt{138} }{6}$ .

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3 years ago

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O.<br> What is the greatest common factor (GCF) of 4 and 64?

Fantom [35]

Answer:

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.... I think 4 is the GCF of 4&64

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3 years ago

A science museum has an average of 424 visitors each day. The museum is open every day. Over a two-week period, how many people

timama [110]

Answer:

5936 people

Step-by-step explanation:

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3 years ago

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Which statement best explains the relationship between lines AB and CD?

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3 years ago

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Find the numbers b such that the average value of f(x) = 4 + 10x − 6x2 on the interval [0, b] is equal to 5.

Tju [1.3M]

Answer:

b = (5±√17)/4 ≈ {0.2192, 2.2808}

Step-by-step explanation:

The average on the interval is found from the integral ...

$\frac{1}{b}\int\limits^b_0 {(4+10x-6x^2)} \, dx =\frac{1}{b}(4b+5b^2-2b^3)\\\\=-2b^2+5b+4$

We want the value of this integral to be 5, so we want to find b such that ...

5 = -2b^2 +5b +4

2b^2 -5b +1 = 0

b^2 -5/2b = -1/2

b^2 -5/2b +25/16 = -1/2 +25/16

(b -5/4)^2 = 17/16

b = (5±√17)/4

The average value of f(x) is 5 on the intervals ...

[0, (5-√17)/4] and [0, (5+√17)/4]

6 0

3 years ago