12m²n² -8mn +1
[6mn-1]•[ 2mn-1]
[ 6mn•2mn + 6mn•-1 + -1•2mn +-1•-1]
= [ 12 m²n² -6mn -2mn +1]
= [ 12m²n2-8mn+1]
.........
Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
