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Sladkaya [172]
3 years ago
12

On a frictionless air track, cart A hits cart B moving at a velocity of 2 meters per second to the right. Which answer predicts

what will happen?
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:

Cart A will bounce to the left while cart B will move right at less than 2 meters per second

Explanation:

You might be interested in
A ball is dropped , find the velocity after 100 m
Marat540 [252]

Answer:

Vf = 44.27 m/s

Explanation:

When a ball is dropped it is acted upon by gravitational force under free fall motion. So, in order to find its final speed we use 2rd equation of motion, as follows:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height lost = 100 m

Vf = Final Velocity = ?

Vi = Initial velocity = 0 m/s (Since, ball starts from rest)

Therefore,

(2)(9.8 m/s²)(100 m) = Vf² - (0 m/s)²

Vf = √(1960 m²/s²)

<u>Vf = 44.27 m/s</u>

5 0
3 years ago
PLEASE HELP ME,, I WOULD BE SO HAPPY
Scrat [10]

Answer:

thanks for the points liar

Explanation:

4 0
3 years ago
A man finds that he has a mass of 100.6 kg. He goes on a diet, and several months later he finds that he has a mass of 96.4 kg.
aleksley [76]

Answer:

1006×10^-1kg

Explanation:

Because 1006kgx10^-1 will give you 100.6kg

8 0
3 years ago
Read 2 more answers
The boys tried a second experiment. They built a balloon car like the one seen here. As the gas in the balloon is released, the
sukhopar [10]

Answer:

newton's third law of motion

Explanation:

The model of balloon car is example of newton's third law of motion which says that to every action there is always and equal and opposite reaction. As the balloon is inflated and then release the nozzle, the rubber contacts and pushes the air forward out of the nozzle, the air pushes back on the rubber and propelling the balloon forward.

5 0
3 years ago
A helicopter is hovering above the ground. Jim reaches out of the copter (with a safety harness on) at 180 m above the ground. A
vesna_86 [32]

Answer:

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

Explanation:

Hi there!

The equation of height and velocity of the package are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the package at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).

v = velocity of the package at a time t.

First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:

v = v0 + g · t

0 = 50.5 m/s - 9.8 m/s² · t

Solving for t:

-50.5 m/s / -9.81 m/s² = t

t = 5.15 s

Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:

h = h0 + v0 · t + 1/2 · g · t²

h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²

h = 140 m

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

6 0
3 years ago
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