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zloy xaker [14]
2 years ago
6

How many values must a 1-D motion problem give you in order to solve it?

Physics
1 answer:
MrRa [10]2 years ago
3 0

Answer:

I think it is B: 3

Explanation:

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What is the connection between electrons and protons
TEA [102]

Answer:

Electrons and protons are connected with one another in term of charge and size.

Explanation:

  • The size of electron and proton is always same in any atom but they possess opposite charge.
  • Electron in any atom carries negative charge where as proton carries the positive charge.
  • In any neutral atom the charge between electron and proton is balanced along with the size.
  • The nucleus of any atom bounds only proton and neutron but the electron is present revolving around the nucleus.
7 0
3 years ago
Which of the following has mechanical energy?
KATRIN_1 [288]
Mechanical energy can have mechanical systems. The only mechanical system in the list is the compressed spring. A car battery and a glowing incandescent lightbulb have electrical energy, a nucleus of atom has potential (internal) energy.

5 0
2 years ago
Read 2 more answers
Answers are - <br><br>A 235 N<br><br>B 376 N<br><br>C 271 N<br><br>D 188 N<br><br>E 470 N
amm1812

Answer:

C

Explanation:

8 0
3 years ago
A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When swit
Ratling [72]

Answer:

The magnitude of angular acceleration is 232.38\ rad/s^2.

Explanation:

Given that,

Initial angular velocity, \omega_i=3500\ rev/min=366.5\ rad/s

When it switched off, it comes o rest, \omega_f=0

Number of revolution, \theta=46=289.02\ rad

We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{-(366.51)^2}{2\times 289.02}\\\\\alpha =-232.38\ rad/s^2  

So, the magnitude of angular acceleration is 232.38\ rad/s^2. Hence, this is the required solution.

6 0
3 years ago
There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long d
Cloud [144]

Answer:

The value is T  =10.1 \ s

Explanation:

From the question we are told that

    The mass of the woman is  m  = 90 \  kg  

    The spring constant of the bungee cord is  k  =  35 \  N/  m

Generally the period of the oscillation (i,e time taken to complete on  cycle ) is mathematically represented as

            T  = 2 \pi *  \sqrt{ \frac{m}{k} }

=>      T  = 2 * 3.142  *  \sqrt{ \frac{90 }{ 35} }

=>      T  =10.1 \ s

3 0
3 years ago
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