Answer:thrust is not a force,upthrust is a force
Explanation:thrust means do something forcefully and upthrust is a force that helps a ship float and pushes an object upwards
Answer:
What is the magnitude of the player 's displacement? A baseball "diamond" is a square, each side of length 27.4 m, with home plate and if each length of the base is 27.4 m, and the baseball player ran to third base,Then, the baseball player is 27.4 feet away from home plate (where he started)below the horizontal.
Explanation:
"v0" means that there are no friction forces at that speed
<span>mgsinΘ = (mv0²/r)cosΘ → the variable m cancels </span>
<span>sinΘ/cosΘ = tanΘ = v0² / gr
</span><span>Θ = arctan(v0² / gr) </span>
<span>When v > v0, friction points downslope: </span>
<span>mgsinΘ + µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ + µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = ((v²/r)cosΘ - gsinΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>
<span>When v > v0, friction points upslope: </span>
<span>mgsinΘ - µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ - µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = (gsinΘ - (v²/r)cosΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>
Answer:
a) F = 18.375N, b) F = 24.5 N
Explanation:
This exercise can be solved using the translational equilibrium equations.
Let's start by fixing a reference system with the horizontal x axis and the vertical y axis, from the statement of the exercise I understand that the wall is vertical and the book is supported on it, therefore the applied force is in the direction towards the wall
a) In this part the force that does not allow the movement of the book is requested, therefore the static friction coefficient must be used (μ_s = 0.8)
X axis
F - N = 0
N = F
Y axis
fr - W = 0
W = fr
where W is the weight of the book.
The friction force has the formula
fr = μ_s N
we substitute
mg = μ_s F
F =
let's calculate
F = 1.5 9.8 / 0.8
F = 18.375N
b) In this case the book is moving so the friction coefficient to use is kinetic ( μ_K = 0.6)
F =
we calculate
F = 1.5 9.8 / 0.6
F = 24.5 N
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