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kodGreya [7K]
3 years ago
15

Could anyone check my Algebra answer?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Answer:

yes -156 is correct

Step-by-step explanation:

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Kendra just bought a new house and needs to buy new sod for her backyard. If the dimensions of her yard are 24.6 feet by 14.8 fe
Serhud [2]

Given:

Dimensions of Kendra's yard are 24.6 feet by 14.8 feet.

To find:

The area of her yard.

Solution:

Let as consider,

Length of yard = 24.6 ft

Width of yard = 14.8 ft

We know that,

Area of a rectangle = Length × Width

Using the above formula, we get the area of her yard.

Area=24.6\times 14.8

Area=364.08

Area of her yard is 364.08 ft² and without including the units ft², we get 364.08.

Therefore, the area of her yard is 364.08.

6 0
3 years ago
If y = -10 -x, find y when x = -2​
arlik [135]

Answer:

y = -8

Step-by-step explanation:

y = -10 - x

y = -10 - (-2)

y = -10 + 2

y = -8

8 0
3 years ago
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Find the value of x. Round the length to the nearest tenth.
Mamont248 [21]
From right triangle trigonometry, we have the following:

\displaystyle{ tan(35^o)= \frac{opposite \ side }{adjacent \ side }, 


where the "opposite side" means the opposite side to angle with measure 35^o, and "adjacent side" means the adjacent side to angle with measure 35^o.

tan(35^o) is a constant which can be found using a calculator.

In the calculator of the pc press: view - scientific - 35 - tan.

 This gives tan(35^o)=0.7


Thus, back in the equation \displaystyle{ tan(35^o)= \frac{opposite \ side }{adjacent \ side } we substitute as follows and solve:


\displaystyle{0.7= \frac{x }{12 }\\\\

x=0.7\cdot12=8.4


Answer: 8.4 cm
5 0
3 years ago
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PLEASE HELP FAST!<br><br><br> what is the length of segment AB? <br> 10<br> 12<br> 13<br> 15
ss7ja [257]

Answer:

13

Step-by-step explanation:

This triangle appears to be 5 units wide and 12 units tall.

Using the pythagorean theorem, a^2 + b^2 = c^2, we get 25 + 144 = 169 or 13^2.

Therefore the answer is 13.

4 0
3 years ago
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Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
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