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masha68 [24]
3 years ago
12

The polyhedron has 120 edges. How many vertices does it have?

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0
(Correct me if I’m wrong in comments)

Answer: 80

Reasoning: A polyhedron can have 30 edges. If this polyhedron has 120 it has 4 times the “other” one. If it has 30 edges it will have 20 vertices, meaning 20*4=80 vertices
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Factor the expression over the complex numbers.<br><br> x2+50
Leto [7]

  x² + 50

= x² - (-50)

= \sqrt{x^{2} } +/- \sqrt{-50}            Side note: \sqrt{-50} = \sqrt{(-1) * 5 * 5} = 5i

= (x + 5i)(x - 5i)

8 0
4 years ago
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What is the SCALE FACTOR (in decimal form) for a ratio of 6:15?
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Given the linear equation 2x + y = 6, perform the necessary operations to put the equation into the proper general form. Explain
likoan [24]

Step-by-step explanation:

The general equation is y = mx + c...

The given equation is 2x + y = 6

Firstly, move everything on the left except the y to the right.i.e.

y = 6 - 2x

Secondly, rearrange the values on the right to look just like the general equation.

y = -2x + 6

The equation is now in proper general form because it matches the format laid down.

3 0
4 years ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
my brother and i walk the same route every day. my beother takes 40minutes to get to school and i take 30minutes to get to schoo
Goryan [66]

In 1 minute, I walk = 1/30

In 1 minute, My brother walk = 1/40

In T minutes, I walk = T*1/30

My brother walk 8 minute before = T + 8

In 1 minute, My brother walk = (T + 8)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 8)*(1/40)

30*(T + 8) = 40*T

30*T + 240 = 40*T

240 = 10*T

T = 24 minutes

hence, I will catch him in 24 minutes.

Take 5 instead of 8.

My brother walk 5 minute before = T + 5

In 1 minute, My brother walk = (T + 5)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 5)*(1/40)

30*(T + 5) = 40*T

30*T + 150 = 40*T

150 = 10*T

T = 15 minutes

Hence, I will catch him in 15 minutes.


6 0
3 years ago
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