Answer:
the probability that the mean number of hours they watch TV is greater than 26.3 hours is 0.034
Step-by-step explanation:
<u>Last part of the question is wrong. It should be:</u>
Find the probability that the mean number of hours they watch TV is greater than 26.3 hours.
P('the mean number of hours the children between ages of 2 and 5 watch TV' >26.3 hours) = P(t>t*) where
t* is the t-score of 26.3 hours. It can be found using the equation:
where
- M is the mean number of hours the children between ages of 2 and 5 watch TV (25 hours)
- s is the standard deviation (3 hours)
- N is the sample size (20)
: ≈1.938
Corresponding p-value with 19 degrees of freedom: P(t>1.938) is ≈ 0.034
1. Multiply 36/10*10/10 because the denominator needs to be 100 (because %= 100)
example: 36/10*10/10=360/100
2. now you have your answer :D
Hope this helps!
Answer:
21.825
Step-by-step explanation:
1 1 1
18.746
3.079
+____
21.825 hope this helps :)
Answer:
B
Step-by-step explanation:
This is easier to follow if you write it out the long way.
g(x) = (x + 3)/x
g(f(x)) = (f(x) + 3)/f(x)
g(x^2 - 7) = (x^2 + 7 + 3)/(x^2 + 7)
g(x^2 - 7) = (x^2 +10 ) / (x^2 + 7)
g(-5) = ( (-5)^2 + 10) / ( (-5)^2 + 7)
g(-5) = ( 25 + 10) / (25 + 7)
g(-5) = 35/32
10,20,30,40,50,60,70
7,14,21,28,35,42,49,56,63,70
So the LCM is 70