Answer:
HCF×LCM=a×b
6×60=a×b
a×b=360
So the numbers are whose product is 360 and LCM is 60
These two numbers can be 6,60 or 12,30
Answer:
Step-by-step explanation:
f(n) = 8 + 3(n) - 3
f(n) = 5 + 3n
f(1) = 5 + 3(1)
f(1) = 8
f(2) = 5 + 3(2)
f(2) = 5 + 6
f(2) = 11
f(3) = 5 + 3*3
f(3) = 14
f(4) = 5 + 3*4
f(4) = 17
Answer:
2/3 and the decimal form is 0.6
Answer:
1650 yards
Step-by-step explanation:
Here, we have to find the minimal spanning tree required to span the neighborhood.
We start from house 1. The minimum distance from house 1 to house 2 is 250 yards. Now from 2, we can go to house 3,4 or 5 all having the equal distances of 400 yard from house 2. So we go to from house 2 to house 3. Now from 3, we go to house 5 which is at a minimum distance of 350 yards. Now from house 5 we go to house 4 with 300 yards and then from house 4 we go to house 6 which is at 350 yards from 4.
Thus the network is complete and the total distance covered is
= 250 + 400 + 350 + 300 + 350
= 1650 yards
This is the minimum distance by which the neighborhood can be wired.
And the tree is
Answer:
Therefore,
The area of the rectangle in terms of width
Step-by-step explanation:
Let the Width of rectangle be 'W' inches.
The length of a rectangle be 'L' inches.
According to the given condition,
Length = 2 + Width
To Find:
Area of Rectangle in terms of Width = ?
Solution:
We have area of rectangle given as
Substituting the values we get
Applying Distributive property A(B+C)=AB+ACwe get
.......As required
Therefore,
The area of the rectangle in terms of width