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svetoff [14.1K]
3 years ago
14

In expression 5y-2xy+6+7x what is the coefficient of x

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0
7. A coefficient is a number or constant placed before the variable in an algebraic expression (e.g., 6 in 5y).
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Eric surveys students at his school and finds that 80% have a pet. He wants to estimate the probability that, if he randomly sel
NNADVOKAT [17]
Yes that is correct what is the question
7 0
3 years ago
I need help with this question
mr Goodwill [35]

Answer:

It would be 1.5m+4 is greater than or equal to 7. This is because 1.5m is the regular rate of growth, plus the 4cm already grown. She wants the hair to be no shorter than 7cm. So, the 15m+4 has to be greater than the 7cm.

Step-by-step explanation:

5 0
3 years ago
7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
loris [4]

Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

6 0
3 years ago
Cory found a job listed in a classified that pays a yearly salary of $54,013. What is the biweekly
Anon25 [30]

Answer:

2077.42

Step-by-step explanation:

There are 52 weeks in a year, so there are 26 "biweekly" weeks in a year.

Cory receieves $54013 per year, so he gets 54013 / 26 dollars biweekly.

We can compute that number, getting 2077.42 dollars.

5 0
3 years ago
What is the equation of the following line? Be sure to scroll down first to see all answer options.
Annette [7]
From the figure the given line passes through the points (0, 0) and (-4, 8).

Recall that the equation of a straight line is given by
\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}

Thus, The equation of the given figure is given by
\frac{y-0}{x-0} = \frac{8-0}{-4-0}= \frac{8}{-4}  \\  \\ -4y=8x \\  \\ y=-2x
8 0
3 years ago
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