Question

Priam has pennies and dimes in a cup holder in his car. The total value of the coins is $4.21. The number of dimes is three less than four times the number of pennies. How many pennies and how many dimes are in the cup?

Answer 1

Answer:

40 dimes and 21 pennies.

Step-by-step explanation:  40 dimes equal 4.00 so just add 21 pennies

Answer 2

Answer:

There are 11 pennies and 41 dimes in the cup.

Step-by-step explanation:

Let the pennies be represented by = p

Let the dimes be represented by = d

The total value of the coins is $4.21. We get the first equation as:

$0.01p+0.10d=4.21$     .......(1)

The number of dimes is three less than four times the number of pennies. We get the second equation as:

$d=4p-3$   ......(2)

Substituting the value of d from (2) in (1)

$0.01p+0.10(4p-3)=4.21$

Solving this we get;

$0.01p+0.4p-0.3=4.21$

=> $0.41p=4.21+0.3$

=> $0.41p=4.51$

We get p = 11

And $d=4(11)-3$ = $44-3$

We get d = 41

Therefore, there are 11 pennies and 41 dimes in the cup.