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denpristay [2]
3 years ago
10

Priam has pennies and dimes in a cup holder in his car. The total value of the coins is $4.21. The number of dimes is three less

than four times the number of pennies. How many pennies and how many dimes are in the cup?
Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

40 dimes and 21 pennies.

Step-by-step explanation:  40 dimes equal 4.00 so just add 21 pennies

dimaraw [331]3 years ago
5 0

Answer:

There are 11 pennies and 41 dimes in the cup.

Step-by-step explanation:

Let the pennies be represented by = p

Let the dimes be represented by = d

The total value of the coins is $4.21. We get the first equation as:

0.01p+0.10d=4.21     .......(1)

The number of dimes is three less than four times the number of pennies. We get the second equation as:

d=4p-3   ......(2)

Substituting the value of d from (2) in (1)

0.01p+0.10(4p-3)=4.21

Solving this we get;

0.01p+0.4p-0.3=4.21

=> 0.41p=4.21+0.3

=> 0.41p=4.51

We get p = 11

And d=4(11)-3 = 44-3

We get d = 41

Therefore, there are 11 pennies and 41 dimes in the cup.

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tino4ka555 [31]

Answer:

8/35

Step-by-step explanation:

1 1/4 = 5/4

3 1/2 = 7/2

5/4 × 7/2

Find the reciprocal. (flip numerator and denomimator)

4/5 × 2/7 = 8/35

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A number k is less than 3 units from 10. <br> What's the absolute value inequality???
Brrunno [24]

It would be: k+3 = 10

subtracting 3 from both sides,

k+3-3 = 10-3

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Which of the fallowing points are the solution to the equation 3x-4y-8=12. Chose all that apply (0,-5) (4,-2) (8,2) (-16,-17) (-
Virty [35]

Answer:

The solutions for the equation are:

(4,-2) and (-16,-17)

Step-by-step explanation:

Given equation:

3x-4y-8=12

Given points:

(0,-5), (4,-2), (8,2), (-16,-17), (-1,-8), (-40,-34)

We will check each point by plugging it in the given equation and see if it satisfies the equation or not.

(0,5)

3(0)-4(5)-8=12

0-20-8=12

-28=12

which is not true. Hence, not a solution.

(4,-2)

3(4)-4(-2)-8=12

12+8-8=12

12=12

which is true. Hence, it is a solution.

(8,2)

3(8)-4(2)-8=12

24-8-8=12

24-16=12

8=12

which is not true. Hence, not a solution.

(-16,-17)

3(-16)-4(-17)-8=12

-48+68-8=12

20-8=12

12=12

which is true. Hence, it is a solution.

(-1,-8)

3(-1)-4(-8)-8=12

-3+32-8=12

21=12

which is not true. Hence, not a solution.

(-40,-34)

3(-40)-4(-34)-8=12

-120+136-8=12

8=12

which is not true. Hence, not a solution.

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3% raise she has receive .
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The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri
VARVARA [1.3K]

Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

⇒ 6/x = 12/6

⇒ 6/x = 2

⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ AD^{2} + BD^{2} = AB^{2}

⇒AD^{2} =AB^{2} - BD^{2}

⇒AD^{2} =6^{2} -3^{2}

⇒AD^{2} =36 - 9 = 25

⇒AD = \sqrt{25}

⇒AD = 5 inches

6 0
3 years ago
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