Question

PLEASE HELP ME FIND THE AREA OF THIS TRIANGLE

Answer 1

Answer:

=49.15 cm²

Step-by-step explanation:

To find the area of the triangle we use the sine formula

A= 1/2ab Sin∅

where A is the area a and b are the lengths of two sides that intersect at a point and ∅ is the angle between them.

a=10 cm

b= 12 cm

∅=55°

A= 1/2×10×12×Sin 55

=49.15 cm²

Answer 2

ANSWER

$Area =49.1 {cm}^{2}$

EXPLANATION

The area of triangle given included angle and length of two sides can be calculated using the formula:

$Area = \frac{1}{2} ab \sin(C)$

Where C=55° is the included angle and a=12 cm , b=10cm are the known sides.

We plug in these values into the formula to get,

$Area = \frac{1}{2} \times 12 \times 10 \sin(55 \degree)$

$Area =49 .14912266$

Rounding to the nearest tenth, the area is

$Area =49.1 {cm}^{2}$