Answer: 0.4512
Step-by-step explanation:
A bit string is sequence of bits (it only contains 0 and 1).
We assume that the 0 and 1 area equally likely to any place.
i.e. P(0)= P(1)= 
The length of bits : n = 10
Let X = Number of getting ones.
Then , 
Binomial distribution formula : 
, where p= probability of getting success in each event and q= probability of getting failure in each event.
Here , 
Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.
Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.
Answer:
<h2>2.6</h2>
Step-by-step explanation:
To solve this, we need to use the Pythagorean theorem to solve this.
The way to solve is by solving for AD by using triangle CAD and then using that result to solve for BD.
3.4² + b² = 6.5²
11.56 + b² = 42.25
42.25 - 11.56 = b²
b = √30.69
b = 5.53985559 or about 5.5
4.9² + b² = 5.5²
24.01 + b² = 30.69
30.69 - 24.01 = 6.68
b = √6.68
b = 2.58456959666 or about 2.6
<h2>EDIT: the other user is incorrect, here's why</h2>
3.4 + 4.5 = 7.9
6.5² + 4.9² = 7.9²
66.26 doesn't equal 62.41
7,000 and 7 hope this helped
Answer:
Option (C)
Step-by-step explanation:
"If the two secants are drawn to a circle form an external points then the product of the measures of one secant segment (inside the circle) and its external segment will be equal to the product of measures of the other secant's segments."
By this property,
8(8 + x) = 9(9 + 7)
64 + 8x = 144
8x = 144 - 64
8x = 80
x = 10
Therefore, Option (C) will be the answer.
