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3 years ago

Look at this set of ordered pairs:

Mathematics

1 answer:

I am Lyosha [343]3 years ago

8 0

Answer:

The answer is yes because no value of x repeats remember a function is for every value of x is exactly one output for y so if you input the same value of x and you get two different values then it's not a function

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Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

4 years ago

Given P(A) = 0.74, P(B) = 0.6 and P(ANB) = 0.494, find the value of

OverLord2011 [107]

Step-by-step explanation: Since we have given, P(A) = 0.75 and P(A|B) =0.8 .

So, P(A∩B) = P(B|A)× P(A) = 0.8×0.75 =0.6 .

We have given P(B|A') = 0.6

P(A’∩B) = P(B|A')×P(A') = 0.6 × 0.25 = 0.15.

P(B) = P(A∩B) + P(A'∩B) = 0.6 + 0.15 = 0.75.

=> P(A|B) = (∩)()=0.60.75

(

∩

)

(

)

0.6

0.75

= 0.8 .

5 0

3 years ago

Solve for 5^3????????

Archy [21]

Answer:

125

Step-by-step explanation:

5*5*5

7 0

3 years ago

I am a factor of 16 but not a multiple of 4. Who am i?

swat32

1 & 2 are the only factors of 16 & not multiples of 4.

Hope this helps!!

6 0

4 years ago

Alvin is six years younger than Elga. The sum of their ages is 62. What is elga’s age?

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

6 0

3 years ago