A rectangles width is one third it’s length, and it’s perimeter is 120 m. Find the dimensions of the rectangle

1 A high school talent show lasted a total of t minutes. There were 2 intermissions that were each the length of 8 the talent sh

Sophie [7]

Answer:

I think f(t)=1/4t

Step-by-step explanation:

Because of you multiply 1/8 times 2, it gives you 1/4. Not 100% sure tho

4 0

2 years ago

What is the solution to the system of equations?

rosijanka [135]

Step-by-step explanation:

3x - 6(2x + 4) = 3

3x - 12x + 24 = 3

-9x + 24 = 3

-9× = -21

x = 2.33

7 0

2 years ago

When the smaller of two consecutive integers is added to two times the larger, the result is 35. Find the integers.

Aleonysh [2.5K]

x+2(x+1)=35

x+2x+2=35

3x=35-2=33

x=33/3=11

smaller number=11

larger number=11+1=12

4 0

3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

Georgia is 7 years younger than 5 times the age of her daughter, Veronica. Veronica will be 14 in 6 years. Part A

kobusy [5.1K]

Answer:

Veronica's age now =8 years

Step-by-step explanation:

Veronica's age now = x years

Georgia's age now = 5x - 7

Veronica age after 6 year = 14

x + 6 = 14

x = 14 - 6

x = 8 years

4 0

3 years ago