Answer:
maybe he trained a lot
Step-by-step explanation:
Hello,
In order to exist ,k>=0
1) sin (180°+x)=-sin (x) ==>sin(203°)=-√k
2) cos² x +sin² x=1==>cos x=√(1+sin² x)=√(1+k)
3)tan (-x)=-tan (x) =-sin (x)/cos (x) =- √k/√(1+k)=√(k/(1+k))
Answer:
5.5 miles over 2 hours--> 5.5/2= 2.75 miles per hour was his average walking speed. 5.5 miles over 2.5 hours --> 5.5/2.5= 2.2 miles per hour on the return trip meaning that his average speed was (2.75-2.2= 0.55) 0.55 miles per hour lower on the return trip
Step-by-step explanation:
I hope this helps you :)
<em><u>-KeairaDickson</u></em>
